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convert the following: 4.0 x 10 6  0.02 = _____ Find the gfw of KOH How many grams are in 0.10 moles of KOH? ACT-prep question: The moon rotates once while going around the earth once. As a result. the moon follows an elliptical path The sun is eclipsed by the moon every seven years.

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  1. convert the following: 4.0 x 106 0.02 = _____ Find the gfw of KOH How many grams are in 0.10 moles of KOH? ACT-prep question: The moon rotates once while going around the earth once. As a result. the moon follows an elliptical path The sun is eclipsed by the moon every seven years. Only one side of the moon faces the Earth. Every fourth year is a leap year. March 3, 2005 Quiz: 2 x 108 K = 39 amu, 0 = 16 amu, H = 1 amu 1(39) + 1(16) + 1(1) =56 amu or 56 g/mole 0.10 moleKOH_56g KOH_ 1mole KOH 5.6 g KOH

  2. http://www.uccs.edu/~tchriste/courses/PES105/105lectures/105lecmotions.htmlhttp://www.uccs.edu/~tchriste/courses/PES105/105lectures/105lecmotions.html here’s a link for anyone interested in planetary motions and the relationship between the earth and sun. Molarity = moles solute Liter of solution Molarity = moles solute dm3 of solution HW 16: #42 49 page 205; #95, 98 page 218; H#96,100 Should be completed today! Tonight’s e.c. HW is # 17

  3. What is the molarity of a solution made from 2.0 g Ca(OH)2 in 500cm3. ?grams  moles 1000 cm3  dm3 Multiply the Numerator – Divide the Denominator Underline the important information. What is the definition of Molarity? Ca = 40.0 2H = 2(1) O= 2(16) 74 g/mole Ca(OH)2 M = moles dm3 1mole Ca(OH)2 74 g Ca(OH)2 1000 cm3 1dm3 M =2.0 g Ca(OH)2 500 cm3 0.054 mole/dm3 or 0.054 M Ca(OH)2 Since you don’t have moles or dm3, look for units that can easily be converted to moles or to dm3

  4. Describe the preparation of the following solution: 1.00 dm3 of 0.3M NiCl2 Underline important information Use the quantity of the given solution as numerator To figure out what to do with 0.3M, you need to know what it means! Since you can’t measure out a mole, you will need to find grams. 0.3 moles dm3 129.5 g NiCl2 mole NiCl2 1.00 dm3 M = moles dm3 Find gfw of NiCl2 Ni =58.7 2 Cl = 2(35.4) 129.5 g/mole Dissolve 38.8 g NiCl2 in enough water to get a volume of 1.00 dm3

  5. Convert cm3 to dm3 Describe the preparation of the following solution: 2.50 x 103 cm3 of 0.400M NiCl2 Underline important information Use the quantity of the given solution as numerator To figure out what to do with 0.3M, you need to know what it means! Since you can’t measure out a mole, you will need to find grams. 2.50 x 103 cm3 = 2500 cm3 = 2.50 dm3 1000 cm3/dm3 0.400 moles dm3 129.5 g NiCl2 mole NiCl2 2.50 dm3 M = moles dm3 Find gfw of NiCl2 Ni =58.7 2 Cl = 2(35.4) 129.5 g/mole Dissolve 130 g NiCl2 in enough water to get a volume of 2.50 dm3

  6. 16, #42 49 page 205; #95, 98 page 218; H#96,100First find moles, then find molarity. • Each Group of two students will come up to the board and explain one problem. This is required, and is worth 10 points. We have no more than 2 days to do this. • EXTRA CREDIT ASSIGNMENT: • Build a mobile showing all of the conversions which are possible from moles to other units. The mobile must be attractive and helpful from 10 feet away. This is worth 25 points. gram formula weight M  volume 6.02x 1023 molecules

  7. HW 17: #50-55 page 208; #101p218 • % = the proportion out of 100 pieces • If there were 100, how much would be … • In a package of M&Ms 15 were brown, 6 were yellow, and 4 were blue. What % were brown? • 15 + 6 + 4 = total number of M&Ms = 25 • 15/25 = the fraction which are brown. • 60% are brown 15 x 100% 25

  8. Find the % nitrogen in ammonia. • NH3 = ammonia N = 14.0 3H = 3 x 1.0 17.0 amu 100% 14.0 amu N 17.0 amu NH3 = 82.4% N in NH3 http://www.ausetute.com.au/percentc.html Tutorial for extra help

  9. 6.00 g Fe(NO3)2 are dissolved in 100.0 cm3 of solution. What is the molarity of this solution? 6.00 g Fe(NO3)2 1 moleFe(NO3)2 1000 cm3 Underline the important information. Then, determine what you know, and want to know. The Molarity is defined as moles per unit volume, so find moles and divide volume! Multiply the Numerator – Divide the Denominator 100.0 cm3 180 g Fe(NO3)2 1 dm3 = 0.334 M Fe(NO3)2 Fe = 56 N = 14 O = 16 1 Fe = 1(56) 2 N = 2(14) 6 O = 6(16) 56 28 96 180.g/mole

  10. H = 2(1.01) O = 16.0 H2O = 18 g/mole % H = 0.112 x 100% 11.2% H % O = 0.889 x 100% 88.9% O To find the % composition of H2O %H = 2.02 g H2 18 g/mole H2O %O = 16.0 g H2 18 g/mole H2O

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