1 / 3

Application Design sludge storage silo

Application Design sludge storage silo. Dr. Hasan Hamouda. Design sludge storage silo. Design a sludge storage silo for one Year capacity Given are with following WWTP Data: Q In = 5000 m 3 , C = 300 mg BOD 5 /l s = 0.9 kg TS / kg BOD 5 SS removal in PS = 60%

vladimir-osborn
Download Presentation

Application Design sludge storage silo

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Application Design sludge storage silo Dr. Hasan Hamouda

  2. Design sludge storage silo Design a sludge storage silo for one Year capacity Given are with following WWTP Data: QIn = 5000 m3, C = 300 mg BOD5/l s = 0.9 kg TS / kg BOD5 SS removal in PS = 60% BOD5 removal in PS = 30% F/M = 0.05 kg BOD5 / kg TS .d TS Eff = 10 mg/l TS max from Thickening tank = 4% TS max from Pressing machine = 18% TS of final dewatering process = 36%

  3. Solution Load in Influence = 5000 m3/d X 300 mg/l = 1500 kg BOD5 , From BOD5 removal in PS = 30%, Load after PS 1500 kg BOD5 X 0.7 = 1050 kg BOD5 From s = 0.9 kg TS / kg BOD5, calculate the m Excess = 1050 X 0.9 = 945 kg TS/d From SS removal in PS = 60%, calculate the m Primary sludge = 1500 X 0.6 = 900 kg TS/d From TS Eff = 10 mg/l, calculate the m Excess, Eff = 5000 X 10 mg/l = 50 kg TS/d (flow in the per flooder) S M total = S m Excess + m Primary sludge + m Excess, Eff = (945 + 900 + 50) kg TS/d = 1895 kg TS/d s total = 1895 kg TS/d /1500 kg BOD5/d = 1.26 kg TS / kg BOD5,elimenated S m total, toDewatering = S m Excess + m Primary sludge = (945 + 900) kg TS/d = 1845 kg TS/d Assumption: TS primary = 20 g/l and from the QR/Q0 Ratio calculate TSR = 10 g/l (for example) So TS to the thickening tank = (20+10)/2 = 15 g/l, Q sludge from the thickening tank = (1845 kg TS/d) / (15 kg/m3) = 123 m3/d Q sludge to the Dewatering machine = (1845 kg TS/d) / (40 kg/m3) = 46 m3/d Q sludge to the liming machine = (1845 kg TS/d) / (180 kg/m3) = 10.25 m3/d Q sludge to the sludge Silo = (1845 kg TS/d + 1845 kg TS( lime)/d ) / (360 kg/m3) = 10.25 m3/d V silo (for one year) = 10.25 m3/d X365 d = 4000 m3

More Related