Dilutions Practice

Dilutions Practice Chalk on the Desk!

#1-Easy How much 0.060 M LiCl solution can be made by diluting 350 mL of 10.0 M LiCl?

#1-Solution How much 0.060 M LiCl solution can be made by diluting 350 mL of 10.0 M LiCl? • V2= 58,000 mL M1V1 = M2V2 (10.0 M)(350 mL) = (0.060 M) x x = 58,333 mL

#2-Medium If water is added to 210 mL of a 0.76 M Ca(OH)2solution until the final volume is 550 mL, what will the molarity of the diluted solution be?

#2-Solution If water is added to 210 mL of a 0.76 M Ca(OH)2 solution until the final volume is 550 mL, what will the molarity of the diluted solution be? • M2= 0.29 M M1V1 = M2V2 (0.76 M)(210 mL) = x (550 mL) x = 0.29018 M

#3- Medium When 32 mL of water is added to 118 mL of a 1.25 M RbCl solution, what will the molarity of the diluted solution be?

#3- Solution When 32 mL of water is added to 118 mL of a 1.25 M RbCl solution, what will the molarity of the diluted solution be? • M2= 0.98 M M1V1 = M2V2 (1.25 M)(118 mL) = x (150 mL) x = 0.98333 M

#4- More Challenging I have 645 mL of a 0.55 M CsBr solution. If I boil the water until the volume of the solution is 0.268 L, what will the molarity of the solution be?

#4- Solution I have 645 mL of a 0.550 M CsBr solution. If I boil the water until the volume of the solution is 0.268 L, what will the molarity of the solution be? • M2= 1.32 M First! 0.268L = 268 mL… or 345mL = 0.345L Then…M1V1 = M2V2 (0.550 M)(645 mL) = x (268 mL) x = 1.32369 M

#5- Extra Challenging! The Mad Chemist received 1.00 liter bottle of 17.0 M solution of H2SO4 sitting in his stock room. He immediately knew he had to dilute the sulfuric acid to 2.0M if he was to store it safely in his stockroom. However, the largest graduated cylinder he had to accurately measure with was only 2.00 L. How many times would the Mad Chemist need to refill the 5.00L vessel?

#5- Solution • The Mad Chemist received 1.00 liter bottle of 17.0 M solution of H2SO4 sitting in his stock room. He immediately knew he had to dilute the sulfuric acid to 2.0M if he was to store it safely in his stockroom. However, the largest graduated cylinder he had to accurately measure with was only 2.00 L. How many times would the Mad Chemist need to refill the 5.00L vessel? • M1V1= M2V2 • (17.0M)(1.00 L)= (2.oM) x • x= 8.50 L • V2= 8.50L subtract from that 1.00L coming from the stock solution= 7.50L of water that must be added….thus, if the graduated cylinder holds 2.00L, then he would need to refill it 3.25 times

Dilutions Practice