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Use of the Tephigram. Converting dew point to mixing ratio. What is the mixing ratio of a parcel of air which has a dew point of 10°C at 800 mb ? Plot T d on the tephigram Read off the value of mixing ratio from the scale at the bottom: 9.8 g kg -1. T D. Converting dew point to RH.
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Converting dew point to mixing ratio What is the mixing ratio of a parcel of air which has a dew point of 10°C at 800 mb? Plot Td on the tephigram Read off the value of mixing ratio from the scale at the bottom: 9.8 g kg-1. TD
Converting dew point to RH What is the relative humidity of a parcel of air which has a temperature of 15°C and dew point of 10°C at 800 mb? We need RH = 100*w/ws w = 9.8 g kg-1 as before ws= 13.6 g kg-1 So RH = 72% T TD
Parcel approximation LCL is the Lifting Condensation Level, the height that a parcel of air must be lifted to reach saturation. In a convective boundary layer it usually corresponds to cloud base Air parcel lifted without mixing and without adding or removing heat SALR z LCL DALR T
Path of air parcel on tephigram Consider a parcel of air lifted from the surface, e.g. by flow over a hill Parcel initially at: 25°C, dew point 8.5°, pressure 1000 mb. We can see that this corresponds to w = 7 g kg-1 As parcel ascends: T follows dry adiabatic Mixing ratio is constant until saturation (T = TD) Then parcel follows saturated adiabatic Cloud Lifting condensation level, LCL = 780 mb
“Normand’s Theorem” Wet bulb potential temperature, θW is used to label saturated adiabats (value of T where adiabat crosses 1000 mb) Project the saturated adiabatic to 1000 mb. It is colder than the (unsaturated) temperature because water is evaporated into the air to keep it saturated, and the energy comes from the air. This is the definition of the wet bulb temperature. Cloud LCL TW T TD Dry adiabatic through the temperature, the mixing ratio line through the dew point, and the saturated adiabatic through the wet bulb temperature, all meet at the LCL
Early morning tephigram over land No cloud Tropopause Boundary layer top Lifting Condensation Level = 930 mb Radiation inversion
Mixing out of radiation inversion – solar heating at the ground Cloud top Cumulus layer LCL in the afternoon Surface warms from 18°C to 23°C
Energy = area on tephigram. What happens if something pushes air parcel upwards? Convective available potential energy = area where Tparcel>Tenvironment Level of free convection Convective inhibition = area where Tparcel<Tenvironment
Deep convection • Develops when CIN is small and CAPE is large • Need some CIN otherwise there is no ‘build-up’ of energy in the boundary layer • Mechanical forcing often needed to overcome CIN – e.g. flow over mountain, sea breeze, cold front • At other times large-scale forcing e.g. trough provides lift.
Orographic uplift – lift each point on tephigram by 50 mb Initial profile. We will use the four coloured altitudes as examples
Orographic uplift – lift each point on tephigram by 50 mb Lift the bottom point through 50 mb. It does not reach the LCL and remains unsaturated 50 mb
Orographic uplift – lift each point on tephigram by 50 mb Lift the next point through 50 mb. It does reach saturation 50 mb
Orographic uplift – lift each point on tephigram by 50 mb Lift the next two points through 50 mb. 50 mb
Orographic uplift – lift each point on tephigram by 50 mb Join up the dots to get the new temperature profile. Hill Cloud
Potential Instability Grey line: temperature profile lifted 50 mb Orange line: SALR from uplifted surface air Slope of grey line > SALR so convectively unstable where saturated: deep thunderstorms would occur on this day over a small hill Saturation