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Starter am w/c 03-Dec-12

Starter am w/c 03-Dec-12. 2.35 g oxalic acid (C 2 H 2 O 4 ) was dissolved into 250 cm 3 water. 19.6 cm 3 of this solution was found to be neutralised by 25 cm 3 NaOH . Calculate the concentration of the NaOH solution. The reaction is given below: C 2 H 2 O 4 + 2NaOH → C 2 O 4 Na 2 + 2H 2 O.

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Starter am w/c 03-Dec-12

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  1. Starter am w/c 03-Dec-12 • 2.35 g oxalic acid (C2H2O4) was dissolved into 250 cm3 water. 19.6 cm3 of this solution was found to be neutralised by 25 cm3NaOH. Calculate the concentration of the NaOH solution. The reaction is given below: C2H2O4 + 2NaOH → C2O4Na2 + 2H2O

  2. Starter am w/c 03-Dec-12 • 2.35 g oxalic acid (C2H2O4) was dissolved into 250 cm3 water. 19.6 cm3 of this solution was found to be neutralised by 25 cm3NaOH. Calculate the concentration of the NaOH solution. moles oxalic acid in 250 cm3 = 2.35/90 = 0.0261 moles oxalic acid in 19.6 cm3 = 0.0261 x 19.6/250 = 0.00205 moles NaOH = 0.00205 x 2 = 0.00409 concNaOH = 0.00409 x 1000/25 = 0.164 moldm-3 (3 s.f.)

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