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d 100

d 0. x. d 50. d 100. t 2 = 4t 1. t 1. d 0. X. X. d 100. Compute c v from Day 1 Lab Data. T 50 = c v t 50 / H dr 2 For U=50%; T 50 = ( p /4)(U%/100) 2 = 0.196 H ave = ½ (H o + H f ) = ½ (1 + 0.9804) = 0.9902 in For doubly-drained lab soil: H dr = ½ H ave = 0.4951 in

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d 100

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  1. d0 x d50 d100

  2. t2 = 4t1 t1 d0 X X d100

  3. Compute cv from Day 1 Lab Data T50 = cvt50 / Hdr2 For U=50%; T50 = (p/4)(U%/100)2 = 0.196 Have = ½ (Ho + Hf) = ½ (1 + 0.9804) = 0.9902 in For doubly-drained lab soil: Hdr = ½ Have = 0.4951 in cv=T50H2dr / t50 cv= (0.196) (0.4951 in)2/(6min) = 8.0 x 10-3 in2/min

  4. Calculate time to 50% consolidationfor a 12 ft doubly-drained clay layer T50=cvt50 / Hdr2 t50= T50 Hdr2/ cv t50-field = (0.196)(72in)2/(8x10-3 in2/min) = 127,008 min = 88 days

  5. B O A OB = 1.15OA

  6. Calculate time to 90% consolidation for a 12 ft doubly drained clay layer • For U=90% • T90 = 1.781 - 0.933 log(100—U%) = 0.848 • T90 = cv t90 / H2dr(avg) • cv = T90 H2dr(avg) / t90 • cv=(0.848)(0.4951 in)2/30.25 min = 0.0068 = 6.8x10-3 in2/min • t90=(0.848)(72in)2/0.0068 = 646,475 min

  7. REMEMBER!!!!!!!! • Select appropriate load cycle and time analysis method for the field conditions • Consider Po and Pf • Consider desired degree of drainage (U=?)

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