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The Skinny on High School Health Statistics. Libby Jones Nicole Miritello Carla Giugliano. Variables taken into consideration:. Height (inches). Weight (lbs). Gender. Age. Vision. Is the relationship between height and weight different across the sexes?
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The Skinny on High School Health Statistics Libby Jones Nicole Miritello Carla Giugliano
Variables taken into consideration: Height (inches) Weight (lbs) Gender Age Vision
Is the relationship between height and weight different across the sexes? • Does adding age as an independent variable change the relationship between height and weight? • Can we prove, statistically that male height is different from female height in high schoolers? Is weight statistically different? • Is female weight more variable than male weight? Is male height more variable than female height? • Is there a statistical difference between male and female mean vision scores? What we hope to learn from our data:
Distribution of Age n = 725
Regression of Weight vs. Height Males n = 370 t-statistic for h = 9.55 p-value = 0.00 95% Confidence Interval: (3.88, 5.89)
Regression of Weight vs. Height Females n = 355 t-statistic for h = 8.24 p-value = 0.00 95% Confidence Interval: (3.99, 6.49)
Regression of Weight vs. Height with a Dummy Variable for SEX sex = 1 if male sex = 0 if female <=males <=females t-statistic for h = 12.58 p-value = 0.00 t-statistic for sex = -2.34 p-value = 0.02 95% Confidence Interval: (4.25, 5.82) 95% Confidence Interval: (-12.49, -1.10)
Regression of Weight vs. Height with a Dummy Variable for sex in the slope sex = 1 if male sex = 0 if female <=males <=females t-statistic for h = 12.33 p-value = 0.00 t-statistic for h*sex = -2.36 p-value = 0.02 95% Confidence Interval: (4.28, 5.91) 95% Confidence Interval: (-.19, -.02)
Taking into account gender, we now predict (weight) with a 95% Confidence Interval of: (148.07, 150.52)
Testing the mean weight for females in high school: vs. t = 1.7024 P > t = 0.04 Reject the Null Note: the sample mean is 143.39
Testing the mean weight for males in high school: vs. t = -2.62 P > |t| = 0.01 Reject the Null Note: the sample mean is 154.96
Testing the mean height for females in high school: vs. t = -8.52 P > |t|= 0.00 Reject the Null Note: the sample height is 63.70
Testing the mean height for males in high school: vs. t = 7.69 P > t = 0.00 Reject the Null Note: the sample height is 67.35
Regression of Weight vs. Height with a Dummy Variable for AGE Age1 = 15 yr olds Age2 = 16 yr olds Age3 = 17 yr olds Age4 = 18 yr olds Males <=Age1 <=Age2 <=Age3 <=Age4 t-stat for h= 9.15, Age2=-.30, Age3=.63, Age4=.25 p-value for h= 0.00, Age2=0.76, Age3=0.53, Age4=0.80
Regression of Weight vs. Height with a Dummy Variable for AGE Age1 = 15 yr olds Age2 = 16 yr olds Age3 = 17 yr olds Age4 = 18 yr olds Females <=Age1 <=Age2 <=Age3 <=Age4 t-stat for h= 8.13, Age2=1.22, Age3= 0.71, Age4= 1.63 p-value for h= 0.00, Age2= 0.23, Age3= 0.48, Age4= 0.10
For females: vs. t forage2 = 0.04 P > |t|= 0.97 Accept the Null
Test: Where: beta1 is for males beta1* is for females <=males <=females t = -.4316 Accept the Null
Regression of Weight vs. Height, Sex, Age Age1 = 15 yr olds Age2 = 16 yr olds Age3 = 17 yr olds Age4 = 18 yr olds sex = 1 if male, sex = 0 if female male female <=Age1 <=Age2 <=Age3 <=Age4 t-stat: h= 12.15 Age2=0.66 Age3=1.00 Age4=1.30 Sex=-2.29 p-value: h= 0.00 Age2=0.51 Age3=0.32 Age4=0.19 Sex=0.02
Taking into account age, we now predict yhat with a 95% Confidence Interval of: (148.06, 150.53)
Testing Variance in weight across gender: vs. F(354,369) ~ 0.79<1.03<1.24 Accept the Null
Testing differences in meanweight across sexes: vs. t = -4.182 P > |t| = 0.000 Reject the Null
Testing Variance in height across gender: vs. F(354,369) ~ 0.84>0.73 Reject the Null Since variances are not equal, we cannot test for the equality of mean height across the sexes.
ANOVA Testing whether weight is dependent on age or not F-statistic: 3.94 Probability > F: 0.01 Reject the Null
Testing Variance in vision across gender: vs. F(354,369) ~(.813, 1.229) 2.0172 > 1.229 Reject the Null Since variances are not equal, we cannot check for equality of mean vision across the sexes.
Testing Variance in vision for 15 and 18 yr olds: Females vs. F(97,41) ~(.0610<.862<1.733) Accept the Null
Testing differences in meanvision for 15 and 18 year olds: Females vs. t = -0.64 P > |t| = 0.522 Accept the Null
Testing Variance in vision for 15 and 18 yr olds: Males vs. F(93,59) ~(0.636<1.553<1.612) Accept the Null
Testing differences in meanvision for 15 and 18 year olds: Males vs. t = 0.42 P > |t| = 0.67 Accept the Null
Possible Errors: • R2 0.20 for all regressions • Weight dependent on other factors • Diet,exercise, genetics, abnormal health conditions, muscle to fat ratio, etc. • Age variable approximates mean age from grade level • Weight and height data may be overestimates due to method of collection • Almost half of data is for 16 year old students • Rounding errors in height and weight measurements • Scale only measured up to 300 lbs
Conclusions: • Sex is statistically significant in determining the relationship between height and weight • Age, as an independent variable, is statistically significant in determining the relationship between height and weight for both males and females • Mean female weight is less than mean male weight at the 95% level of significance • At the 95% level of significance, variance of weight in females does not differ from that of males • Male height is more variable than that of females at the 95% level of significance • Because variance in vision is not equal between males and females, we could not compare male and female mean vision scores by an unpaired t-test