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Final presentation

Smart FPGA Based SAT Solver. Saleem Sabbagh & Najeeb Darawshy Supervisors: Mony Orbach, Technion & Ilia Averbouch, IBM. Final presentation. Started at: Spring 2012 Duration: Semester. outline. What is SAT Reminder - description and goals Memory Technique GSAT Flow diagram

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Final presentation

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  1. Smart FPGA Based SAT Solver Saleem Sabbagh & Najeeb Darawshy Supervisors: Mony Orbach, Technion & Ilia Averbouch, IBM Final presentation Started at: Spring 2012 Duration: Semester

  2. outline • What is SAT • Reminder - description and goals • Memory Technique • GSAT • Flow diagram • Controller • Circuit diagram • Resources usage and times • Runtimes • Conclusions • Notes

  3. What is sat • Boolean Satisfiability Problem • Given a Boolean propositional formula, does there exist assignment of values such that the formula becomes true? • e.g., given the formula f=(x1 ˅ x3˅ -x4) ˄ (x4) ˄ (x2 ˅ -x3) are there values of x1,x2,x3,x4 that produce f=‘1’

  4. Reminder - Compilation times *Clock frequency is 50M [Hz]

  5. Reminder - Runtimes *Clock frequency is 50M [Hz]

  6. Reminder • In the first project this was our “what’s next” slide. • Two approaches • Improving compilation times by: • Understanding Altera compilation algorithms to enable faster SAT-specific FPGA ready files. • Smart use of memory on FPGA to implement SAT. • Improving runtimes by designing smart sat solver instead of inefficient LFSR random generator

  7. Memory Technique • Two memory entities • SAT is represented by ROM. • Based on the DE2’s M4K built in memory blocks. • We convert the DIMACS CNF SAT instance into a memory description file and put it in the memory. • The ROM address= variable’s number. • contentof the address = representation of the clauses which the variable appears in. • Each clause is represented by a shiftregister that will save the number of variables that satisfy each clause according to the current assignment.

  8. Memory Technique – Example Example.mif Example.cnf c Example CNF format filec p cnf 4 31 3 -4 04 02 -3 0 DEPTH = 4 ; % Variables % WIDTH = 6 ; % Clauses*2 % ADDRESS_RADIX = DEC; DATA_RADIX = BIN; CONTENT BEGIN 0 : 000011; 1 : 110000; 2 : 100011; 3 : 001110; END; For assignment 1101 Clause number 1’s shift register status will be:

  9. Memory Technique – In Memory System Content Editor

  10. GSAT GSAT(intMaxtries, intVariables) { For (i=1 to Maxtries) { V = a random instantiation of the variables; For (i = 1 to Variables) { p = variable – who’s negation yields largest increase in number of satisfied clauses; V = V with p flipped; } if (F(V) is true) return V; } } *Take random variable in case of equality.

  11. GSAT - EXAMPLE • Initialize random assignment 01111 • Total satisfied clauses = 20 (out of 21) • Flip each variable and see how many added satisfied clauses: • Variable 1 : 0 new satisfied clauses. • Variable 2 : -1 new satisfied clauses. • Variable 3 : -2 new satisfied clauses. • Variable 4 : 0 new satisfied clauses. • Variable 5 : 1 new satisfied clauses. • Maximum = variable 5, flip it. • Assignment = 11111. • Total satisfied clauses = 21 (out of 21) => SUCCESS!

  12. Flow diagram Reset Convert PC In System Memory Content Editor SignalTap DE2

  13. Controller attempts == allowed • Init • Reset circuit • Random Assignment • Clauses Init • Var by var run and save to shiftreg • Flipping • Flip variable value • Sum satisfied clauses • Advance var var == total vars var == total vars • Finish • Output satisfying assignment • Maximum • Increase attempts if max <= 0 • Flip max var and save to shiftreg satisfied == total clauses attempts == allowed

  14. Circuit diagram

  15. Resources usage and time • LEs: 20,562/33,216 (62%) • M4Ks: 102/105 (97%) • Registers: 8,355/34,593 (24%) • Compilation time: 4:12 minutes.

  16. Runtimes *Clock frequency is 12.5M [Hz] (compared to 50M [Hz])

  17. Conclusions • Runtime was reduced DRASTICALLY. • Due to GSAT implementation. • From data appears to be polynomial increase of 4th order. • We expect the more the number of variables is the polynomial relationship will decrease, again due to a much harder locality problem. • Random runtimes for same instance due to initial random assignment. • Two degrees of freedom: total attempts, random bit.  can improve runtimes. • Compilation time = NO compilation time. • Use Quartus’s built-in In Memory Content Editor to change the SAT for all variables sizes.

  18. Notes • Tried two approaches for clauses representation in memory: • Encoded Clause Representation • For each variable, only clauses which the variable appears in are included in the memory and are represented by binary encode of the clause number. • Less memory usage, more LEs, alters sat, only 14 clauses per variable  special design (decoders, special software support). • Direct Clause Representation • All the clauses are included in the memory each is represented by two bits to indicate if the variables appears in it and what value satisfies it. • More memory usage, less LEs, doesn’t restrict design. • We have developed two Java based applications • SAT converter from cnf to mif format according to our clause representation. • SAT satisfying value asserter. • Currently our design supports 5-sat (5variables per clause) only, can be increased with minimal effort.

  19. Notes 2 • Support maximum of 200 variables and 860 clauses due to the limit of the M4Ks (of the DE2). • 408Kb of memory was used. • To measure runtimes we have used benchmark SAT instances, as well as cppbased satisfiable/unsatisfiable SAT generator used in official SAT competitions which was used for runtimes analysis. • We have measured between 4 to 6 instances of SAT with the same variable number and took the average. • The standard deviation of the runtimes was of the same order of the average, meaning that the results vary a lot between instances due to the local minimum problem.

  20. Real time demonstration • Follow us please.

  21. Thank you! • Questions?

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