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Passing Structures Lesson xx

Passing Structures Lesson xx. Objectives. Review functions and passing arguments Passing structures Program passing structures. Passing Arguments. fun (a, 5.6); void fun ( int x, float y) { . . . }. Passing Structures. struct student { long id; int age;

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Passing Structures Lesson xx

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  1. Passing StructuresLesson xx

  2. Objectives • Review functions and passing arguments • Passing structures • Program passing structures

  3. Passing Arguments fun (a, 5.6); void fun (int x, float y) { . . . }

  4. Passing Structures struct student { long id; int age; char sex; }; int main ( ) { student s; . . . fun (s); . . . } void fun (student x) { . . . }

  5. Program Specifications Write a program that does the following: Reads in today’s date 2. Calculates and prints tomorrow’s date

  6. Flowchart T F ! EOM T F EOY Add 1 to day New month New year

  7. Code – Part 1 #include <iostream> using std::cin; using std::cout; using std::endl; struct date { int month; int day; int year; }; intlastDayOfMonth(const date&); // prototype intleapYear(const date&); // prototype int main() {   date today, tomorrow; cout << "enter today's date (mm ddyyyy):" << endl; cin >> today.month >> today.day >> today.year;

  8. Code - Part 2 if (today.day != lastDayOfMonth(today))   { tomorrow.day = today.day + 1; tomorrow.month = today.month; tomorrow.year = today.year;   }   else if (today.month == 12)   { tomorrow.day = 1; tomorrow.month = 1; tomorrow.year = today.year + 1;   }   else   { tomorrow.day = 1; tomorrow.month = today.month + 1; tomorrow.year = today.year;   }

  9. Code Part 3 cout << "tomorrow's date is "     << tomorrow.month << " " << tomorrow.day    << " " << tomorrow.year << endl;   return 0; } intlastDayOfMonth(const date& d) { int num; intdaysPerMonth[12] =     {31, 28, 31, 30, 31, 30,      31, 31, 30, 31, 30, 31};   if (leapYear(d) && (d.month == 2))     num = 29;   else     num = daysPerMonth[d.month - 1];   return num; }

  10. Code – Part 4 intleapYear(const date& da) { int flag = 0;   if ((((da.year % 4) == 0)     && ((da.year % 100) != 0))     || ((da.year % 400) == 0))     flag = 1;   return flag; }

  11. Structure Definition struct date { int month; int day; int year; };

  12. Declarations intlastDayOfMonth(const date&); // prototype intleapYear(const date&); // prototype int main() {   date today, tomorrow; tomorrow today.month tomorrow.month tomorrow.day today.day today.year tomorrow.year today

  13. Input cout << "enter today's date (mm ddyyyy):" << endl; cin >> today.month >> today.day >> today.year; 10 today.month tomorrow.month 17 tomorrow.day today.day 2020 today.year tomorrow.year tomorrow today

  14. Test for Not End of Month if (today.day != lastDayOfMonth(today))   { tomorrow.day = today.day + 1; tomorrow.month = today.month; tomorrow.year = today.year;   }   int x = lastDayOfMonth(today); if (today.day != x )   { tomorrow.day = today.day + 1; tomorrow.month = today.month; tomorrow.year = today.year;   }

  15. Explanation int x = lastDayOfMonth(today); if (today.day != x )   { tomorrow.day = today.day + 1; tomorrow.month = today.month; tomorrow.year = today.year;   }

  16. New Year else if (today.month == 12)   { tomorrow.day = 1; tomorrow.month = 1; tomorrow.year = today.year + 1;   }

  17. New Month else   { tomorrow.day = 1; tomorrow.month = today.month + 1; tomorrow.year = today.year;   }

  18. Print Tomorrow’s Date cout << "tomorrow's date is "     << tomorrow.month << " " << tomorrow.day    << " " << tomorrow.year << endl;   return 0; }

  19. lastDayof Month ( ) Function intlastDayOfMonth(const date& d) { int num; intdaysPerMonth[12] =     {31, 28, 31, 30, 31, 30,      31, 31, 30, 31, 30, 31};   if (leapYear(d) && (d.month == 2))     num = 29;   else     num = daysPerMonth[d.month - 1];   return num; }

  20. lastDayof Month ( ) Code intlastDayOfMonth(const date& d) { int num; intdaysPerMonth[12] =     {31, 28, 31, 30, 31, 30,      31, 31, 30, 31, 30, 31};   if (leapYear(d) && (d.month == 2))     num = 29;   else     num = daysPerMonth[d.month - 1];   return num; }

  21. leapYear() Function intleapYear(const date& da) { int flag = 0;   if ((((da.year % 4) == 0)     && ((da.year % 100) != 0))     || ((da.year % 400) == 0))     flag = 1;   return flag; }

  22. Advantage of Passing Structures int x = lastDayOfMonth (today); intlastDayOfMonth(const date & d) int x = lastDayOfMonth ( m, d , y ); int= lastDayOfMonth (int mm, intdd, intyy)

  23. Summary Review functions and passing arguments Passing structures Program passing structures

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