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Quadractic Word Problems

Quadractic Word Problems. Solutions to Homework & New Practice Problems. Answers to the easier Problems. #6 Height-81.125 ft Distance to Home Plate 156.2 ft #7 20 fixtures # 8 11.8 seconds ; 4 seconds #9 .25 seconds #10 Earth 4.5 sec; 2.9 sec Jupiter ( Jupiter)

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Quadractic Word Problems

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  1. Quadractic Word Problems Solutions to Homework & New Practice Problems

  2. Answers to the easier Problems • #6 Height-81.125 ft • Distance to Home Plate 156.2 ft • #7 20 fixtures • # 8 11.8 seconds ; 4 seconds • #9 .25 seconds • #10 Earth 4.5 sec; 2.9 sec Jupiter ( Jupiter) • #11 .19 seconds to 1.3 sec

  3. Answers continued #13 $10 Price Revenue $13,599 #14 2 sec #15 1000 tires; $20 per tire #17 1.3 sec ; 10.5 sec #18 100 ft is the max height; 5 seconds

  4. #16 • Draw a picture of the parabola: Left Ordered Pair will be ( 0,0); Right ordered pair will have to be (20,0) Because it says you land ten feet from the fence and the fence is the axis Of symmetry which means it is equidistant on both sides. This also means The vertex is ( 10,10) because the height is 10 and the distance is between The two other points. Now put all three points in stat edit, and pick Quad Func #5 Equation is -.1x^2 +2x

  5. #19 • Vertex is ( 59.6, 36.8) • Maximum Height of Punt will be 36.8 ft • Nearest Defensive Player is 5 ft. This is an x value because x is the horizontal distance • Per Flow Chart, if given an x value, look up in table to find y. Look 5 up and table will indicate that the player must reach 7.65 ft to block the punt. • To determine how far it would go before it hit the ground, you would put 0 in y2 and find the right intersection point. The answer is 119.7 ft.

  6. #20 • Find the vertex. X is distance, y is height • (315, 630) • Max height is 630 ft • To find how wide is the arch, double the x of the vertex because remember a parabola is equidistant from the vertex • Arch is 630 ft wide

  7. #21 • X represents price; y represents profit • Domain refers to x values. Domain then has to be x > o because you would not have negative or 0 price • Daily profit is a y value, so as flow chart says you look up the x values in the table • $277.55 profit at $.40; $210 at $.85 • Max Profit is $300 Price to make max profit is $.55

  8. Practice Problem One • Big Bertha, a cannon used in WW1 could fire shells incredibly long distances. The path of the shell could be modeled by • Y=-0.0196x^2 +1.37x, where x was the horizontal distance traveled in miles and y was the height in miles. How far could Big Bertha fire a shell? What was the shell’s maximum height?

  9. PP#1 Answer • 70 miles distance; 24 miles height • To find distance, put 0 in y1 and equation in y2 Then find right intersecting point • To find height, find maximum using calculator or find –b/2a and look up in table.

  10. Practice Problem #2 • According to legend, in 1589 the Italian scientist Galilei dropped two rocks of different weights from the top of the Leaning Tower of Pisa. He wanted to show that the rocks would hit the ground at the same time. Given the equation • h= -16t^2 +h0 ; where h0 is initial height and the tower is 177ft high, how long would it take for the rocks to hit the ground?

  11. PP#2 Answer • 3.3 sec

  12. Practice Problem #3 • The equation h= 0.019s^2 gives the height h ( in feet) of the largest ocean waves when the wind speed is s knots. How fast is the wind blowing if the largest waves are 15ft high? Do Algebraically and using calculator.

  13. PP#3 Answer • 28.1 knots

  14. Practice Problem # 4 • For the years 1989-1996, the amount A ( in billins of dollars) spent on long distance telephone calls in the United States can be modeled by A=0.560t^2 + 0.488t +51 where t is the number of years since 1989. In what year did the amount spent reach 60 billion?

  15. PP#4 Answer • 1993

  16. Practice Problem # 5 • You and your friend are playing tennis. Your friend lobs the ball high into the air, hitting 3 ft above the court with an initial vertical velocity of 40 ft per second. You back up and prepare to hit an overhead smash to win the point. Use the model h= -16t^2 +v0t + h0 to write an equation giving the height of the lobbed tennis ball as a function of time.

  17. PP#5 continued At what time t does the ball reach its maximum height above the court? What is the maximum height? If you plan to hit the smash when the ball falls to a height of 8 feet above the court, how long do you have to prepare for the shot? If you plan to hit the smash ball between 6ft and 9ft above the court, what are your possible preparation times?

  18. PP# 5 Answers • H= -16t^2 + 40t +3 • 1.25 seconds, 28 ft • Apx. 2.37 seconds • Between 2.34 seconds to 2.42 seconds

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