1 / 20

Experiment 14

Experiment 14. Enthalpy of Hydration. Purposes and Goals. The purpose of this experiment is to use Hess’s Law to determine the enthalpy change ( Δ H) for the hydration of an anhydrous compound. Introduction. Conservation of energy Hess’s Law of Heat Summation

JasminFlorian
Download Presentation

Experiment 14

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Experiment 14 Enthalpy of Hydration

  2. Purposes and Goals • The purpose of this experiment is to use Hess’s Law to determine the enthalpy change (ΔH) for the hydration of an anhydrous compound.

  3. Introduction • Conservation of energy • Hess’s Law of Heat Summation • Alternative view of Hess’s Law: ΔH does not depend on how I get from reactants to products.

  4. I can use this idea to determine ΔH for a reaction which is hard to study directly. Example: graphite  diamond C(s, gr)  C(s,di)

  5. A thermochemical cycle ΔH1 C(s,gr) + O2(g) CO2(g) ΔH2ΔH3 C(s,di) + O2(g)

  6. DH1 = DH2 + DH3 • The direct conversion of graphite to diamond (corresponding to DH2) is hard to measure, but the two combustions (DH1 and DH3) are easy to measure. We can determine DH2 indirectly from DH1 and DH3. • DH2 = DH1 - DH3

  7. Your experiment ΔH1 MgSO4(s) + xs H2O(l) Mg2+(aq) + SO42-(aq) + 7 H2O(l) ΔH2ΔH3 MgSO4.7 H2O(s) + xs H2O(l)

  8. Calorimetry • Calorimetry---measuring heat flow • Fundamental idea: Qreaction = -Qsolution • Qsolution = C ΔT • C = (mass of solution) x (specific heat of the solution)

  9. Safety • Aprons and glasses • Thermometers are fragile and expensive; don’t use a thermometer as a stirring rod!

  10. Procedure • Work in pairs. • Needed equipment: 100-mL graduated cylinder, stirring rods, thermometers, 2 thermometer clamps, 2 calorimeter cups, ring stand, ring. • Same setup as Expt. 6 (CHEM 1031 lab).

  11. One run with MgSO4, two with hydrate. • Weigh empty calorimeter cup. Record mass on data sheet. • Weigh solute (about 7.50 g of MgSO4, 15.35 g of hydrate). Idea: equal moles of solute in samples.

  12. Add 100 mL water to cup; measure temperature every 30 seconds for five minutes. • Add MgSO4; use stirring rod (NOT THERMOMETER) to dissolve solute quickly. • Measure temperature every minute for fifteen minutes. After run is over, measure and record mass of cup plus solution.

  13. Weigh second calorimeter cup; add water and measure temperature for five minutes as before. • After 5 minutes, add MgSO4.7 H2O. Measure temperature for 15 minutes as before. Measure and record mass of cup and solution.

  14. Discard solution (sink); add 100 mL of water and repeat run. After 5 minutes, add second portion of MgSO4.7 H2O. Measure temperature for 15 minutes as before. Measure and record mass of cup plus solution; you will use the same mass of empty cup for both runs.

  15. Calculations • Draw a graph of temperature vs time for your experimental data. Each run is a separate graph. • Extrapolate the temperature lines before and after adding solute to the time at which solute was added.

  16. DT = Tfinal – Tinitial • C = mass of solution x specific heat of solution (specific heat of solution = 3.837 J g-1 deg-1) • Qreaction = - C DT • (Good model: p. 14-3 of lab manual!)

  17. Average DH values for solution of hydrate. ΔH1 MgSO4(s) + xs H2O(l) Mg2+(aq) + SO42-(aq) + 7 H2O(l) ΔH2ΔH3 MgSO4.7 H2O(s) + xs H2O(l)

  18. You have calculated the heats of solution of MgSO4 (DH1 ) and of MgSO4.7 H2O (DH3). • The enthalpy of hydration (DH2) is DH2 = DH1 - DH3.

More Related