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Power; Rotational Energy. Power Rotational work, power, and kinetic energy. Serway & Jewett 7.5, 10.4, 10.8. Recall:. Power. Power is the rate at which work is done:. Average power = Work/time. units: 1 J/s =1 watt (W).
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Power; Rotational Energy • Power • Rotational work, power, and kinetic energy. Serway & Jewett 7.5, 10.4, 10.8 Physics 1D03 - Lecture 21
Recall: Physics 1D03 - Lecture 21
Power Power is the rate at which work is done: Average power = Work/time units: 1 J/s =1 watt (W) Instantaneous power: Average over an infinitesimal time dt, displacement ds; the work is dW = F • ds, and power is Physics 1D03 - Lecture 21
f F r ds = rdq d Rotational Work A bit of work, dW, is done in turning a nut through a tiny angle d : So, and so for a constant torque, Physics 1D03 - Lecture 21
Power: So, (again, angular velocity must be expressed in radians/second). Physics 1D03 - Lecture 21
Quiz A power screwdriver is intended to provide a torque of 0.5 N·m while turning at 120 revolutions per minute. The minimum power needed from the motor will be about • 60W • 6 W • 1 W Physics 1D03 - Lecture 21
vi w but so K = ½ Iw 2 Kinetic energy of a rotating rigid body: Add up the kinetic energies of the particles: Physics 1D03 - Lecture 21
Quiz A wheel is spun up to speed by a motor that produces a constant power. It takes time t to reach an angular velocity . Assuming negligible friction at the axle, how long does it take to reach twice this angular velocity? Physics 1D03 - Lecture 21
Example A computer hard drive has four 100-gram platters (disks), 10 cm in diameter. (Uniform thin disk: I= ½ M R2) • How much kinetic energy do they have at 7200 rpm? • How long does a 7-watt motor take to get the drive up to speed? Physics 1D03 - Lecture 21
Example: Big Ben, a tower clock in London has an hour hand 2.7m long with a mass of 60kg and a minute hand 4.5m long with a mass of 100kg. Calculate the rotational kinetic energy of the two hands. (I=1/3 ML2) Big Ben Physics 1D03 - Lecture 21
Quiz A cone-shaped top is launched by winding a string of length L around the top, and pulling with a constant force F. How should the string be wound to do the greatest amount of work on the top? • wind it around the thick end • wind it around the thin end • it doesn’t matter how it is wound • not enough information F Physics 1D03 - Lecture 21
Summary • Power: P=dW/dt = F • v • Rotation: dW = t dq, P = t w, K = ½ Iw 2 • Suggested Problems:Chapter 7, problems 35, 40a (5910W) • Chapter 10, problems 21.(5th ed): • Chapter 7, problems 37, 47a • Chapter 10, problems 23. Physics 1D03 - Lecture 21