TBM 9.09 m A.A.D.

1. Approximate North Main Gate TBM 9.09 m A.A.D. Burnaby Building Top of door level at entrance to structures laboratory Ground level at entrance to structures laboratory TBM 10.00 m A.A.D. Point 1 Start at a TBM outside the main entrance of Burnaby Building and obtain the RL values of three points before closing onto another TBM near the main gate.

2. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good TBM 10.00m AAD It is important to complete details at the top of booking forms or on every page of field books.

3. Key BS Level Posn. TBM

4. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good TBM 10.00m AAD 1.546 11.546 10.000 HPC = RL + BS HPC = 10.000 + 1.546 = 11.546 We now signal to the staff person to move to the next point. As the next required point is too far away (it is also round a corner) we will eventually need to move the instrument. So, we must move the staff to a change point (CP), to allow us to move the instrument to a better position later on.

5. Key BS FS CP Level Posn. TBM

6. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good 1.546 11.546 10.000 TBM 10.00m AAD New staff position therefore a new row. Each row represents a staff position. 1.562 C.P. 9.984 RL = HPC - FS RL = 11.546 - 1.562 = 9.984 After we make a FS and we have calculated the new RL we are finished with that instrument position. Move the Instrument (about the CP) to a new position where we can see the CP and also the next point we want the RL value of.

7. Key IS BS FS CP Level Posn. TBM

8. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good 1.546 11.546 10.000 TBM 10.00m AAD 1.562 C.P. 9.984 Same staff position as last reading therefore the same row 1.418 11.402 HPC = RL + BS HPC = 9.984 + 1.418 = 11.402

9. Key IS BS FS CP Level Posn. TBM It is not the last from this position (we can see the next points) so it is not a FS This reading is not the first so it is not a BS So it is known as an INTERMEDIATE SIGHT (IS)

10. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good 1.546 11.546 10.000 TBM 10.00m AAD 1.562 C.P. 1.418 9.984 11.402 New staff position therefore a new row 1.390 10.012 Point 1 RL = HPC - IS RL = 11.402 - 1.390 = 10.012

11. Key IS BS FS CP Level Posn. TBM

12. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good 1.546 11.546 10.000 TBM 10.00m AAD 1.562 C.P. 1.418 9.984 11.402 1.390 10.012 Point 1 New staff position therefore a new row 1.281 GL Struct. Lab Door 10.121 RL = HPC - IS RL = 11.402 - 1.281 = 10.121

13. Key IS BS FS CP Level Posn. TBM

14. Burnaby Building L 52 07/10/98 M.A.R. M.A.R. Good 1.546 11.546 10.000 TBM 10.00m AAD 1.562 C.P. 1.418 9.984 11.402 1.390 10.012 Point 1 1.281 GL Struct. Lab Door 10.121 New staff position therefore a new row -2.420 Top Struct. Lab Door 13.822 Requires an inverted staff i.eturn the staff upside down Read and then book the staff with a negative sign The negative sign will keep all the calculations correct RL = HPC - IS RL = 11.402 - (-2.420) = 11.402 + 2.420 = 13.822

15. Key IS BS FS CP Level Posn. TBM The last point required is the TBM. However it is too long a sight. So we need a CP. This will be the last sighting from this position Therefore a FS

16. Burnaby Building L 52 Site: …………………………………. Instrument: …………………………………. 07/10/98 M.A.R. Date: …………………………………. Observer: …………………………………. M.A.R. Good Weather: …………………………………. Booker: …………………………………. TBM 10.00m AAD 1.546 11.546 10.000 11.402 9.984 C.P. 1.562 1.418 Point 1 1.390 10.012 10.121 GL Struct. Lab Door 1.281 -2.420 Top Struct. Lab Door 13.822 New staff position therefore a new row 1.321 CP 10.081 RL = HPC - FS RL = 11.402 - 1.321 = 10.081 Last Reading -- FS -- Move the instrument

17. Key IS BS FS CP Level Posn. TBM

18. Burnaby Building L 52 Site: …………………………………. Instrument: …………………………………. 07/10/98 M.A.R. Date: …………………………………. Observer: …………………………………. M.A.R. Good Weather: …………………………………. Booker: …………………………………. TBM 10.00m AAD 1.546 11.546 10.000 11.402 9.984 C.P. 1.562 1.418 Point 1 1.390 10.012 10.121 GL Struct. Lab Door 1.281 -2.420 Top Struct. Lab Door 13.822 1.321 CP 10.081 1.011 11.092 Same staff position as last reading therefore the same row HPC = RL + BS HPC = 10.081 + 1.011 = 11.092

19. Key IS BS FS CP Level Posn. TBM

20. Burnaby Building L 52 Site: …………………………………. Instrument: …………………………………. 07/10/98 M.A.R. Date: …………………………………. Observer: …………………………………. M.A.R. Good Weather: …………………………………. Booker: …………………………………. TBM 10.00m AAD 1.546 11.546 10.000 11.402 9.984 C.P. 1.562 1.418 Point 1 1.390 10.012 10.121 GL Struct. Lab Door 1.281 -2.420 Top Struct. Lab Door 13.822 1.011 11.092 1.321 CP 10.081 2.007 TBM 9.09m AAD 9.085 New staff position therefore a new row RL = HPC - FS RL = 11.092 - 2.007 = 9.085

21. Before we look more fully at the results we will complete the second half of the levelling exercise Key IS BS FS CP Level Posn. TBM

22. Top of door level at entrance to structures laboratory Ground level at entrance to structures laboratory Point 2 Key IS BS FS CP Level Posn. TBM

23. Key IS BS FS CP Level Posn. TBM

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31. Key IS BS FS CP Level Posn. TBM