300 likes | 459 Views
CSCE 212 Chapter 3: Arithmetic for Computers. Instructor: Jason D. Bakos. Lecture Outline. Review of topics from 211 Overflow Binary Multiplication Binary Division IEEE 754 Floating Point Floating-Point Addition and Multiplication MIPS Floating-Point. Review.
E N D
CSCE 212Chapter 3: Arithmetic for Computers Instructor: Jason D. Bakos
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Review • Binary and hex representation • Converting between binary/hexidecimal and decimal • Two’s compliment representation • Sign extention • Binary addition and subtraction
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Overflow • Overflow for unsigned addition • Carry-out • Overflow for unsigned subtraction • No carry-out • Overflow for signed • Overflow causes exception • Go to handler address 80000080 • Registers BadVAddr, Status, Cause, and EPC used to handle • SPIM has a simple interrupt handler built-in that deals with interrupts
Overflow • Test for signed ADD overflow: addu $t0,$t1,$t2 # sum but don’t trap xor $t3,$t1,$t2 # check if signs differ slt $t3,$t3,$zero # $t3=1 if signs differ bne $t3,$zero, No_OVF xor $t3,$t0,$t1 # signs of operands same, compare sign of result slt $t3,$t3,$zero bne $t3,$zero,OVF • Test for unsigned ADD overflow: addu $t0,$t1,$t2 # sum but don’t trap nor $t3,$t1,$zero # invert bits of $t1 (-$t1–1), 232-$t1-1 sltu $t3,$t3,$t2 # 232-$t1-1 < $t2, 232-1 < $t1+$t2 bne $t3,$zero,OVF
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Binary Multiplication 1000 x 1001 1000 0000 0000 1000 1001000 multiplicand multiplier product
Binary Multiplication works with signed but must sign extend shifts
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Binary Division For signed, convert to positive and negate quotient if signs disagree
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Fixed-Point • Need a way to represent fractional numbers in binary • Fixed-point • Assume a decimal point at some location in a value: • Example: • 6-bit (unsigned) value • = 1x21 + 0x20 + 1x2-1 + 1x2-2 + 0x2-3 + 1x2-4 • For signed, use two’s compliment
Precision • Assume we have 4 binary digits to the right of the point… • Convert .8749 to binary… • .1101 = .8125 • Actual value – represented value = .0624 (approaches 2-4)
Floating Point • Floating point represent values that are fractional or too large • Expressed in scientific notation (base 2) and normalized • 1.xxxx2 * 2yyyy • xxxx is the significand (fraction) and yyyy is the exponent • First bit of the significand is implicit • Exponent bias is 127 for single-precision and 1023 for double-precision • IEEE 754 standard • Single-precision (2x10-38 to 2x1038) • bit 31: sign of significand • bit 30..23 (8) exponent (2’s comp) • bit 22..0 (23) significand • Double-precision (2x10-308 to 2x10308) • Significand is 52 bits and the exponent is 11 bits • Exponent => range, significand => precision • To represent: • zero: 0 in the exponent and significand • +/- infinity: all ones in exponent, 0 in significand • NaN: all ones in exponent, nonzero signficand
Conversion • To convert from decimal to binary floating-point: • Significand: • Use the iterative method to convert the fractional part to binary • Convert the integer part to binary using the “old-fashioned” method • Shift the decimal point to the left until the number is normalized • Drop the leading 1, and set the exponent to be the number of positions you shifted the decimal point • Adjust the exponent for bias (127/1023) • When you max out the exponent, denormalize the significand
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
Floating-Point Addition • Match exponents for both operands by un-normalizing one of them • Match to the exponent of the larger number • Add significands • Normalize result • Round significand
Example • Assume 11-bit limited representation: • 1 bit sign bit • 6 bit significand (precision 2-6 = 0.0156) • 4 bit exponent (bias 7) • range 1 x 2-7 (7.8 x 10-3) to 1.111111 x 28 (5.1 x 102) • (assuming no denormalized numbers)
Floating-Point Multiplication • Un-bias and add exponents • Multiply significands • Move point • Re-normalize • Set sign based on sign of operands
Accurate Arithmetic • Keep 2 additional bits to the right during intermediate computation • guard and round • Worst case for rounding: • Actual number is halfway between two floating point representations • Accuracy is measured as number of least-significant error bits (units in the last place (ulp)) • IEEE 754 guarantees that the computer is within .5 ulp (using guard and round)
Lecture Outline • Review of topics from 211 • Overflow • Binary Multiplication • Binary Division • IEEE 754 Floating Point • Floating-Point Addition and Multiplication • MIPS Floating-Point
MIPS Floating-Point • $f0 - $f31 coprocessor registers • Used in pairs for doubles • Arithmetic: [add | sub | mul | div].[s | d] • Data transfer: lwc1, swc1 (32-bits only) • Conditional branch: • c.lt.[s | d] (compare less-than) • bclt (branch if true), bclf (branch if false) • Register transfer: • mfc1, mtc1 (move to/from coprocessor 1, dest. is first)