Kinetics Lesson 4 PE Diagrams

1. Kinetics Lesson 4 PE Diagrams

2. Potential Energy Diagrams Kinetic Energy (kJ) Heat energy due to the motion of particles. Simulation Potential Energy or Enthalpy (H). ΔH means change in enthalpy It is also called the heat of the reaction because it tells you how much heat or KE was produced or consumed by the reaction. Bond Energy (kJ)

3. PE + KE = Total Energy is constant Conservation of Energy PE KE ΔH Reaction Type Decreases Increases -veexothermic Increases Decreases +veendothermic When PE (bond energy) decreases it is converted into KE which increases. Remember that KE is heat energy, so it gets hotter and it is exothermic.

4. Potential Energy Diagrams Exothermic Show the change in potential energy or enthalpy during a successful collision. Standard Notation: H2 + I2 → 2HI + 170 kJ ΔH Notation: H2 + I2 → 2HI ΔH = -170 kJ Both notations indicate an exothermic reaction. The first indicates that 170 KJ of KE are produced, while the second shows that the PE decreases by 170 KJ. On the right Or negative

5. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 KJ 1. An H2 and I2 approach each other

6. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 1. Reactants H2 and I2 approach each other Reactants PE Reaction Path

7. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 2. They collide and become anActivated Complex PE Reaction Path

8. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 2. They collide and become anActivated Complex Unstable Reaction Intermediate High PE Low KE Bonds Break & Form Reactant bonds break Activated complex bonds form PE Reaction Path

9. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 3. New bonds form and products separate PE Reaction Path

10. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 3. New bonds form and products separate activated complex bonds break product bonds form PE Reaction Path

11. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 3.New bonds form and products separate Activated Complex Reactants Products PE Reaction Path

12. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 3.New bonds form and products separate PE Reaction Path Ea(for) Ea(rev)

13. Lets Explore the Potential Energy Changes during a Single Collision H2 + I2 → 2HI + 170 kJ 3.New bonds form and products separate PE Reaction Path Ea Ea(rev) ΔH = -ve

14. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ H2 + I2 → 2HI ΔH = -170 kJ   600 400 200 0 PE (KJ) Reaction Path

15. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ H2 + I2 → 2HI ΔH = -170 kJ   600 reactants 400 200 0 PE (KJ) Reaction Path

16. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ H2 + I2 → 2HI ΔH = -170 kJ   600 reactants Ea 400 200 0 PE (KJ) Reaction Path

17. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ H2 + I2 → 2HI ΔH = -170 kJ   600 reactants Ea 400 ΔH 200 0 PE (KJ) Reaction Path

18. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ. H2 + I2 → 2HI ΔH = -170 kJ   600 reactants Ea 400 ΔH 200 0 PE (KJ) Reaction Path

19. Potential Energy Diagrams Endothermic Standard Notation: I2 + Cl2+ 100 kJ → 2ICl ΔH Notation: I2 + Cl2 → 2ICl ΔH = + 100 kJ Both notations indicate an endothermic reaction. The first indicates that 100 kJ of KE are consumed, while the second shows that the PEincreases by 100 kJ. on left or positive

20. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path

21. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path

22. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path

23. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path

24. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path ΔH = + 100 KJ

25. Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path ΔH = + 100 KJ

26. Draw the PE diagram if the enthalpy of the reactants is 400 KJ and the energy of the activated complex is 600 KJ.   I2 + Cl2+ 100 KJ → 2ICl  PE 600 400 200 Reaction Path Ea ΔH = + 100 KJ

27. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600   400   200 PE (KJ) Reaction Path

28. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600   400   200 PE (KJ) Reaction Path

29. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600   400   200 PE (KJ) Reaction Path Ea (rev) = 400 kJ

30. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600   400   200 PE (KJ) Reaction Path Ea (rev) = 400 kJ

31. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600 Ea (for) = 200 kJ   400   200 PE (KJ) Reaction Path Ea (rev) = 400 kJ

32. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600 Ea (for) = 200 kJ   400   200 PE (KJ) Reaction Path Ea (rev) = 400 kJ

33. Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ   600 Ea (for) = 200 kJ   400   200 PE (KJ) Reaction Path Ea (rev) = 400 kJ ΔH = -200 kJ

34. Exothermic Reaction

35. Exothermic Reaction Uncatalyzed reaction

36. Exothermic Reaction Uncatalyzed reaction Catalyzed reaction

37. Exothermic Reaction Reactants Products

38. Exothermic Reaction Reactants Products stronger bonds

39. Exothermic Reaction Downhill in PE KE is produced

40. Exothermic Reaction Downhill in PE KE is produced Ea(for)(uncat)

41. Exothermic Reaction Downhill in PE KE is produced Ea(for)(uncat) Ea(for)(cat)

42. Exothermic Reaction Downhill in PE KE is produced Ea(for)(uncat) Ea(for)(cat) H

43. Exothermic Reaction Downhill in PE KE is produced Ea(for)(uncat) Ea(for)(cat) Ea(rev)(cat) H

44. Exothermic Reaction Downhill in PE KE is produced Ea(for)(uncat) Ea(rev)(uncat) Ea(for)(cat) Ea(rev)(cat) H

45. PE(kJ) 500 400 300 200 100 0 reaction path H forward = H reverse = Ea forward uncat = Ea reverse uncat = Ea forward cat =

46. PE(kJ) 500 400 300 200 100 0 reaction path H forward = -300 kJ H reverse = Ea forward uncat = Ea reverse uncat = Ea forward catalyzed =

47. PE(kJ) 500 400 300 200 100 0 reaction path H forward = -300 kJ H reverse = +300 kJ Ea forward uncat = Ea reverse uncat = Ea forward catalyzed =

48. PE(kJ) 500 400 300 200 100 0 reaction path H forward = -300 kJ H reverse = +300 kJ Ea forward uncat = 100 kJ Ea reverse uncat = Ea forward catalyzed =

49. PE(kJ) 500 400 300 200 100 0 reaction path H forward = -300 kJ H reverse = +300 kJ Ea forward uncat = 100 kJ Ea reverse uncat = 400 kJ Ea forward catalyzed =

50. PE(kJ) 500 400 300 200 100 0 reaction path H forward = -300 kJ H reverse = +300 kJ Ea forward uncat = 100 kJ Ea reverse uncat = 400 kJ Ea forward catalyzed = 50 kJ