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This experiment aims to calculate the viscosity of glycerin using the time taken for a steel ball to fall through the fluid. Viscosity measures a fluid's resistance to flow, with higher viscosity indicating greater thickness. Follow precise steps and data collection to determine glycerin's viscosity accurately.
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Objective: • To determine the viscosity of • glycerin.
Theory: Viscosity is a measure of the resistance of a fluid which is being deformed by either shear stressor tensile stress. In everyday terms (and for fluids only), viscosity is "thickness". Thus, water is "thin", having a lower viscosity, while honey is "thick", having a higher viscosity. Viscosity describes a fluid's internal resistance to flow and may be thought of as a measure of fluid friction.
η = 2 r2 ( ρ2 – ρ1 ) g . T. 1 -- . ------------------------------ . ------ 9 s 1 + 2.4 r --- R Where η = viscosity h = distance of fall = 80 Cm = 0.8m R = radius of the fluid cylinder = 0.022m t = time for fall = ______ sec r = radius of the ball = 0.002m ρ2 = density of sphere = 7800 kg/m3 ρ 1= density of fluid = 1261 kg/m3 g = acceleration due to gravity = 9.8 m/s2
Take a look of these pictures! • Lava • Oil
Tools: Steel ball Glycerin Holding magnet with clamp Stand base V shape Magnets Stop watch
Steps: • Drop the ball into the glycerin. • Start the stop watch as you drop the ball. • As soon as the ball has reached the bottom, stop the stop watch. • Read the time of fall t .
Data: Complete Table 1