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Is { a 2n | n > 0} Non Regular? The debate rages…

Is { a 2n | n > 0} Non Regular? The debate rages…. s = a p x = ε |xy|  p y = a (p-2) |y| > 0 z = a 2 xyz = ε a (p-2) a 2 For i  0, is xy i z  { a 2n | n > 0} Think of s this way: (aa) * aa x is ε , (aa) * is y, aa is z.

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Is { a 2n | n > 0} Non Regular? The debate rages…

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  1. Is { a2n | n > 0} Non Regular?The debate rages… s = ap x = ε |xy|  p y = a(p-2) |y| > 0 z = a2 xyz = εa(p-2) a2 For i  0, is xyiz  { a2n | n > 0} Think of s this way: (aa)*aa x is ε, (aa)* is y, aa is z

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