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Auto dissociation of Water. Water molecules allow protons to be transferred between molecules & an equilibrium is established. HOH (l) + HOH (l) H 3 O + ( aq ) + OH - ( aq ) Overall: 2H 2 O (l) H 3 O + ( aq ) + OH - ( aq )
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Auto dissociation of Water Water molecules allow protons to be transferred between molecules & an equilibrium is established. HOH (l) + HOH(l) H3O+ (aq) + OH-(aq) Overall: 2H2O (l) H3O+ (aq) + OH-(aq) Keq = Kw = [H3O+] [OH-] = 1.0 x 10-14 at 250C Anytime H3O+ions or OH- ions are present, this equilibrium is automatically established & this regulates the allowable concentrations of H3O+ & OH-.
Thus, Kw = [H3O+] [OH-] can be used to calculate [H3O+] & [OH-] in acidic & basic solutions. In a neutral solution [H3O+] [OH-] = 1 x 10-7 M (i.e. pH=7) SAMPLE PROBLEMS: 1) In a certain container of H2O it was found that the [OH-] was 1.0 x 10-4. What is [H3O+]? What is the pH?
2) A 0.0001 M HCl (a strong acid) solution will have a pH of what? What would be [OH-] be? 3) Ca(OH)2 is a strong base. If a 0.000 05M solution dissociates in water, what will the pH be?
Easy (basic) Math Definition of pH [H3O+] = 10-pH M Ex) solution where [H3O+] = 0.001 M (10-3M). Find the pH. [H3O+] = 0.001 M or 1 x 10-3 M so pH = 3 Ex) Find the pH of a 0.0001 M solution of HCl. We need to find the [H3O+]. Since HCl is a strong acid, it completely dissociates. HCl + H2O H3O+ + Cl- Initial: 0001M 0 M so [H3O+] = 0.0001 M = 1 x 10-4 0 M .0001 M pH = 4
Log arithmetic Definition of pH pH – the pH of a solution is defined as the negative of the log of the hydronium ion concentration Ex) [H3O+] = 3.25 x 10-3 M, find the pH. Answer: pH = -log 3.25 x 10-3= Ex) [H3O+] = 1.44 x 10-10 M, find the pH. Answer: pH = -log 1.44 x 10-10 =
Finding Concentrations from pH values Ex) pH = 2.80, find [H3O+]. We must work in reverse (take the “antilog” of the negative pH). pH = 2.80 [H3O+] = antilog -2.8 = Ex) pH = 11.4 [H3O+] = antilog -11.4 =
Calculating pOH The pOH is the pH value of a solution using the concentration of the OH- ions. pH + pOH = 14 Ex) What is the pH of a 3.41 x 10-4 M NaOH solution?