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Exercise. How many different lunches can be made by choosing one of four sandwiches, one of three fruits, and one of two desserts?. 24. Exercise. How many different lunches can be made by choosing one of four sandwiches, one of three fruits, one of two desserts, and one of two beverages?. 48.
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Exercise How many different lunches can be made by choosing one of four sandwiches, one of three fruits, and one of two desserts? 24
Exercise How many different lunches can be made by choosing one of four sandwiches, one of three fruits, one of two desserts, and one of two beverages? 48
Exercise How many ways can four separate roles be filled if four people try out? 24
Exercise How many ways can four separate roles be filled if seven people try out? 840
Exercise How many ways can seven separate roles be filled if seven people try out? 5,040
Permutation A permutation is a way of arranging r out of n objects (if r ≤ n).
Fundamental Principle of Counting If there are p ways that a first choice can be made and q ways that a second choice can be made, then there are p× q ways to make the first choice followed by the second choice.
n Factorial The product of n natural numbers from n down to one is called n factorial. The symbol for “factorial” is an exclamation mark, and n! = n(n – 1) … (1). (0! = 1 by definition.)
Example 1 Evaluate 6! 6(5)(4)(3)(2)(1) = 720
Example Evaluate 5! 120
Example Evaluate 8! 40,320
Formula for the Permutation of n Objects Taken n at a Time—nPn To find the number of permutations of n distinct objects taken n at a time, find the product of the positive integers n down through one: nPn = n(n – 1)(n – 2) … (2)(1) = n!
Example 2 Find the number of permutations of the letters in the word saved.
To find the number of permutations of n distinct objects taken r at a time, use the formula nPr = . n!(n – r)! Formula for the Permutation of n Objects Taken r at a Time—nPr
5 x 4 x 3 x 2 x 12 x 1 5!(5 – 3)! = = Example 3 Find the number of permutations of the five letters s, a, v, e, and d taken three at a time. 5P3 = 5 x 4 x 3 = 60
8!5! = 8!(8 – 3)! = 8(7)(6)(5)(4)(3)(2)(1)(5)(4)(3)(2)(1) = Example 4 Find the number of permutations of eight distinct things taken three at a time. 8P3 = (8)(7)(6) = 336
Example Evaluate 5P3. 60
Example Evaluate 9P4. 3,024
Example Find the number of ways ten books can be arranged on a bookshelf. 10P10 = 10! = 3,628,800
Example Find the number of possible class schedules for a student taking six different classes. 6P6 = 6! = 720
Example Find the number of different ways of choosing 17 committee chairpersons from the 51 senators in the majority party. 51P17 = 51! ÷ 34! = 5.25 × 1027
Example In a race involving six people, how many different orders are possible for the top three finishers? 6P3 = 6! ÷ 3! = 120
Example How many ways are there to select a jury foreman and subforeman from among the twelve jurors? 12P2 = 12! ÷ 10! = 132
Example Find the number of ways of arranging ten books on a bookshelf if five are math books and five are history books and each category must be grouped together. 5! x 5! x 2 = 28,800
Exercise Write an expression in the form nPr to represent the number of permutations in the following situations.
Exercise Select first, second, and third place out of 500 contestants. 500P3
Exercise Elect a president, vice president, secretary, and treasurer from a class of twenty-eight students. 28P4
Exercise How many different two-digit whole numbers can you make from the digits 2, 4, 6, and 8 if no digit appears more than once in each number? 4P2
Exercise How many different three-letter arrangements are there of the letters of the alphabet? 26P3