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Methods Sensitive to Free Radical Structure. Resonance Raman Electron-Spin Resonance (ESR) or Electron Paramagnetic Resonance (EPR). Motivation. Absorption spectra of free radical and excited states are generally broad and featureless Conductivity is not species specific
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Methods Sensitive toFree Radical Structure • Resonance Raman • Electron-Spin Resonance (ESR) or Electron Paramagnetic Resonance (EPR)
Motivation • Absorption spectra of free radical and excited states are generally broad and featureless • Conductivity is not species specific • Conductivity is additive with respect to ionic content of the cell
Specific Vibrations? • Now have vibrational spectroscopy in laser flash photolysis, usually in organic solvents • Water is a good filter of infrared and masks vibrational features of free radicals • Raman is weak, second-order effect • What about Resonance Enhanced Raman?
LIGHT SCATTERING Medium Ei + - Incident light Emergent light 0 sScattered light Rayleigh s = 0 s = 0 mn Raman Pi = αij Ej P = Induced electric dipole moment E = Electric field of the electromagnetic radiation αij= Elements of polarizability tensor G.N.R. Tripathi
ENHANCEMENT OF RAMAN SCATTERING e em 0 n mn m Imn = Const. I0 (0 mn)4 I( )mn I2 ( ) mn = (1/h) MmeMen/ (em 0 + i e) e + non-resonant terms (via αij) G.N.R. Tripathi Probability Amplitude
RESONANCE RAMAN em >> 0 Normal Raman em - 0 ~ 0 Resonance Raman |( ) mn 2 = Const. × (MmeMen)2 / 2 Enhancement up to 107-108 Pulse radiolysis time-resolved resonance Raman Identification, structure, reactivity and reaction mechanism of short-lived radicals and excited electronic states in condensed media Relevance: Theoretical chemistry, chemical dynamics, biochemistry, ,paper and pulp-industry, etc. G.N.R. Tripathi
2,2’- bipyridyl dppz = dipyridophenazine [Ru(bpy)2dppz]2+ bound to DNA NO DNA present DNA present 1000 1200 1300 1400 Raman shift (cm-1) http://www.lot-oriel.com/site/site_down/cc_appexraman_deen.pdf
Selection Rulesfor the Amplitudes of Transitions Franck-Condon Factor Electronic Transition Elements (Dipole allowed) For Resonance enhancement both must be non-zero http://www.personal.dundee.ac.uk/~tjdines/Raman/RR3.HTM
Relationship to Radiationless Transitions and Absorption dP(nm)/dt = (42/h) |Vmn|2 FC (Em) This is a probability. Quantum mechanics usually calculates amplitudes which are “roughly the square root” (being careful about complex numbers) Taking the square root, shows that the amplitudes for radiationless transitions are first-order in the interaction V Likewise, simple absorption and spontaneous emission are first-order processes with regard to an interaction Vrad
Connection to Wavefunctions So we can use the path integral to see how one non-stationary state (f) at time ta propagates into another at time tb In terms of the stationary states of the system
Expansion of part of exponential for small potentials Putting this back into the Amplitude Kv(b,a) gives a perturbation expansion of the path integral
Interpretation of First Term Represents propagation of a free particle from (xa,ta) to (xb,tb) with no scattering by the potential b V a
Interpretation of Second Term b tb Particle moves from a to c as a free particle. At c it is scattered by V[x(s),s] = Vc. After it moves as a free particle to b. The amplitude is then integrated over xc, namely over all paths. t tc c ta a x
Physical Meaning of 2nd Term Represents propagation of a particle from (xa,ta) to (xb,tb) that may be scattered once by the potential at (xc,tc) b V c a
Interpretation of Third Term Represents propagation of a particle from (xa,ta) to (xb,tb) that may be scattered twice by the potential, once at (x(s),s) and once at (x(s),s) b V a
Selection Rules (A-term) A-term: Condon approximation - the transition polarizability is controlled by the pure electronic transition moment and vibrational overlap integrals The A-term is non-zero if two conditions are fulfilled: (i) The transition dipole moments [mr]ge0 and [ms]eg0 are both non-zero. (ii) The products of the vibrational overlap integrals, i.e. Franck-Condon factors, <ng|e><e|mg> are non-zero for at least some values of the excited state vibrational quantum number .
Consideration of Franck-Condon Factors <ne|g> = 0 orthogonal <ne|g> 0 Non-symmetric Or Symmetric <ne|g> 0 <ne|g> 0 Totally Symmetric Vibrational Mode Totally Symmetric Vibrational Mode http://www.personal.dundee.ac.uk/~tjdines/Raman/RR4.HTM
Why must these modes totally symmetric vibrations? He(Q) = Qg + DQ + (k/2)Q2 Hg(Q) = Qg + (k/2)Q2 All terms in the Hamiltonian must be totally symmetric, Therefore, the displacement DQ must also be totally symmetric