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Solution to the Continous Flow Stirred-Tank Reactor Problem

Solution to the Continous Flow Stirred-Tank Reactor Problem. ChE 479. Problem Set-up. The tank is well mixed; Input flow rate is 0.085 m 3 /min; Tank Volume is V=2.1m 3 ; C Ainit = 0.925 mole/m 3 ; C A0 = 0.925 mole/m 3 ; The system is initially at steady state

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Solution to the Continous Flow Stirred-Tank Reactor Problem

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  1. Solution to the Continous Flow Stirred-Tank Reactor Problem ChE 479

  2. Problem Set-up • The tank is well mixed; • Input flow rate is 0.085 m3/min; • Tank Volume is V=2.1m3; • CAinit = 0.925 mole/m3; • CA0= 0.925 mole/m3; • The system is initially at steady state • A first order reaction is carried out • A--->B • Assumptions: • Density of liquid constant • Reaction rate is proportional to the concentration of the reactant • r = -kCA • Process is isothermal CA(t) CA0

  3. Governing Equations Diving by MWAt and letting t--->0 gives

  4. Initial Conditions Initial Conditions require that we know the concentration of the process output before any perturbation occurred. This means that we must know the output concentration at the previous steady state, when the input concentration was: CA0=Cainit=0.925 mole/m3

  5. Solving the Governing Differential Equation First Order Linear Equation: The genral solution is given by: Is referred to as the Integrating Factor where

  6. Solving the Governing Differential Equation You immediately recognize the this equation is linear and first order ! With And

  7. Solving the Governing Differential Equation So we can calculate the Integrating Factor: Multiple both sides of the governing differential equation Then the right hand is a perfect derivative:

  8. Solving the Governing Differential Equation Now we can integrate the differential equation: But the form of CA0(t) is known. In the example we have discussed it is a constant equal to the value of the input concentration after the perturbation:

  9. Initial Condition The Initial Condition will determine the integration constant:

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