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the Mole !

It’s time to learn about. the Mole !. What's The Difference Between Roast Beef And Pea Soup?. Anyone Can Roast Beef. Stoichiometry. Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should be able to:.

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the Mole !

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  1. It’s time to learn about . . . the Mole !

  2. What's The Difference Between Roast Beef And Pea Soup? Anyone Can Roast Beef.

  3. Stoichiometry

  4. Stoichiometry : Mole Ratios to Determining Grams of ProductAt the conclusion of our time together, you should be able to: • Review the conversion of particles or grams to moles • Determine mole ratios from a balanced chemical equation • Determine the amount of product produced when given the amount of reactants

  5. Review the Molar Mass of Compounds • The molar mass (MM) of a compound is determined by adding up all the atomic masses for the molecule (or compound) • Ex. Molar mass of CaCl2 • Avg. Atomic mass of Calcium = 40.08g • Avg. Atomic mass of Chlorine = 35.45g • Molar Mass of calcium chloride = 40.08 g/mol Ca + (2 X 35.45) g/mol Cl 110.98 g/mol CaCl2 20 Ca40.08 17Cl 35.45

  6. My new book on GOLF will give the reader valuable playing tips and insider information I've gained through my years of lessons, struggles and experiments. Here are just a few of the chapter titles:  Chapter 5 - When to Give the Ranger the Middle Digit. Chapter 14 – The Best Time to Let a Foursome Play through Your Twosome.

  7. Calculations molar mass Avogadro’s number Grams Moles Particles Everything must go through Moles!!!

  8. Flowchart Atoms or Molecules Divide by 6.02 X 1023 Multiply by 6.02 X 1023 Multiply by atomic/molar mass from periodic table Moles Divide by atomic/molar mass from periodic table Mass (grams)

  9. Things my Mother taught me… WEATHER.      "This room of yours looks as if a tornado went through it."

  10. Chocolate Chip Cookies!! 1 cup butter 2 eggs 1/2 cup white sugar 1 teaspoon salt 1 cup packed brown sugar 1 teaspoon vanilla extract 2 1/2 cups all-purpose flour 1 teaspoon baking soda 2 cups semisweet chocolate chips Makes 3 dozen How many eggs are needed to make 3 dozen cookies? How much butter is needed to make 6 dozen cookies? How many cookies could I make if I had plenty of everything but only had 1½ cups white sugar?

  11. Cookies and Chemistry…Huh!?!? • Just like chocolate chip cookies have recipes, chemists have recipes as well • Instead of calling them recipes, we call them chemical equations • Furthermore, instead of using cups and teaspoons, we use moles • Lastly, instead of eggs, butter, sugar, etc. we use chemical compounds as ingredients

  12. Chemistry Recipes: #1 on Stoichiometry between 2 Compounds • Looking at a reaction tells us how much of something you need to react with something else to get a product (like the cookie recipe) • Be sure you have a balanced reaction before you start! Balance #1 on your worksheet!! • Example: 2 Ag + Cl2  2 AgCl • This reaction tells us that by mixing 2 moles of silver with 1 mole of chlorine we will get 2 moles of silver chloride • What if we wanted 4 moles of AgCl? • 10 moles? • 5 moles?

  13. Let’s sit down and figure this out!!

  14. Mole Ratios • These mole ratios can be used to calculate the moles of one chemical from the given amount of a different chemical • Example: How many moles of chlorine are needed to react with 5 moles of silver (without any silver left over)? 2 Ag + Cl2 2 AgCl 5 Ag + 2.5 Cl2 5 AgCl

  15. x 1 mol Cl2 2 mol Ag Question Answer 2 Ag+ Cl2 2 AgCl # moles of Cl2 = 5 mol Ag = 2.5 mol Cl2

  16. 70.90 g Cl2 1 mol Cl2 Mole-Mole Conversions • 2.5 moles of Cl2 would be how many grams? 2 Ag + Cl2 2 AgCl 2.5 mol Cl2 x = 177.25 g Cl2

  17. Try #2Molar Mass of Fe(OH)3 = 106.88 g/mol

  18. Now # 3…Molar Mass of SiO2 = 60.09 g/mol

  19. Another Why - Maxine If  lawyers are disbarred and clergymen defrocked, then  doesn't it follow that electricians can be delighted, musicians denoted, cowboys deranged,   models deposed, tree surgeons debarked, and dry cleaners depressed?

  20. Stoichiometry : Mole Ratios to Determining Grams of ProductLet’s see if you can: • Review the conversion of particles or grams to moles • Determine mole ratios from a balanced chemical equation • Determine the amount of product produced when given the amount of reactants

  21. Start your HomeLearning NOW!!

  22. Stoichiometry Continued:

  23. Stoichiometry : Mole Ratios to Determining Grams of ProductAt the conclusion of our time together, you should be able to: • Determine the amount of product produced when given the amount of reactants

  24. Mass-Mass Conversions • Most often we are given a starting mass and want to find out the mass of a product we will get (called theoretical yield) or how much of another reactant we need to completely react with it (no leftover ingredients!) • Now we must go from grams to moles, to mole ratios, and back to grams of the compound we are interested in.

  25. “Disorder in the American Courts”These are statements people actually said in court, word for word, taken down and now published by court reporters. ATTORNEY:  She had three children, right? WITNESS:     Yes. ATTORNEY:  How many were boys? WITNESS:    None. ATTORNEY:   Were there any girls? WITNESS:      Your Honor, I think I need a different attorney. Can I get a new attorney?

  26. Remember This?? Moles Atoms or Molecules Mass (grams)

  27. Moles of A  Moles of B Atoms or Molecules Atoms or Molecules Mass (grams) Mass (grams)

  28. Practice Mass-Mole-MassConversion of Grams to Grams #1 • How many grams of iron are required to make 86.7 grams of FeS • Fe + S8 FeS • 8 Fe + S8 8 FeS

  29. x 8 mol Fe x 55.85 g Fe 8 mol FeS 1 mol Fe x 1 mol FeS 87.92 g FeS Mass-Mole-Mass • 8 Fe + S8 8 FeS 86.7 g FeS = 55.1 g Fe

  30. x 1 mol S8 8 mol FeS x 1 mol FeS 87.92 g FeS How many moles of S8 are needed? • 8 Fe + S8 8 FeS 86.7 g FeS = 0.123 mol S8

  31. Some Things Just Take a Lot of Work!!!

  32. Stoichiometry : Mole Ratios to Determining Grams of ProductLet’s see if you can: • Determine the amount of product produced when given the amount of reactants

  33. Mass-Mole-MassNow Try #2…

  34. Don’t you just love these types of problems???

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