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Highland Science Department Concentration

Highland Science Department Concentration. Highland Science Department Concentration Concentration: the amount of solute per quantity of solvent. Highland Science Department Concentration Methods of determining concentration: 1. mass/volume % = solute mass (g) x 100%

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Highland Science Department Concentration

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  1. Highland Science Department Concentration

  2. Highland Science Department Concentration Concentration: the amount of solute per quantity of solvent

  3. Highland Science Department Concentration Methods of determining concentration: 1. mass/volume % = solute mass (g) x 100% solution volume (mL)

  4. Highland Science Department Concentration Methods of determining concentration: 1. mass/volume % = solute mass (g) x 100% solution volume (mL) e.g. saline solution that contains 0.9 g of sodium chloride dissolved in 100 mL =0.9 % (m/v)

  5. Highland Science Department Concentration Methods of determining concentration: 2. mass/mass % = solute mass (g) x 100% solution mass (g)

  6. Highland Science Department Concentration Methods of determining concentration: 2. mass/mass % = solute mass (g) x 100% solution mass (g) e.g. 100 g of toothpaste contains 0.76 g of sodium fluoride = 0.76 % (w/w)

  7. Highland Science Department Concentration Methods of determining concentration: 3. volume/volume % = solute volume (mL) x 100% solution volume (mL)

  8. Highland Science Department Concentration Methods of determining concentration: 3. volume/volume % = solute volume (mL) x 100% solution volume (mL) e.g. 100 mL of rubbing alcohol contains 70 mL of isopropyl alcohol in water. = 70 % (v/v)

  9. Highland Science Department Concentration concentrations of very trace amounts of solute (e.g. pollutants) can be expressed as: parts per million (ppm) parts per billion (ppb) parts per trillion (ppt)

  10. Highland Science Department Concentration parts per million = solute mass x 106 solution mass similar to mg/L

  11. Highland Science Department Concentration parts per million = solute mass x 106 solution mass similar to mg/L parts per billion = solute mass x 109 solution mass similar to μg/L

  12. Highland Science Department Concentration e.g. A 1.6 kg fish was found to contain 0.6 mg of mercury. If the acceptable level is 0.5 ppm, would this fish be safe to eat?

  13. Highland Science Department Concentration e.g. A 1.6 kg fish was found to contain 0.6 mg of mercury. If the acceptable level is 0.5 ppm, would this fish be safe to eat? G: fish mass = 1.6 kg x = 1.6 x 103 g mercury mass = 0.6 mg x = 6 x 10-4 g acceptable level = 0.5 ppm

  14. Highland Science Department Concentration e.g. A 1.6 kg fish was found to contain 0.6 mg of mercury. If the acceptable level is 0.5 ppm, would this fish be safe to eat? U: safety of the fish S: 1. calculate ppm = solute mass x 106 solvent mass 2. compare with acceptable level

  15. Highland Science Department Concentration e.g. A 1.6 kg fish was found to contain 0.6 mg of mercury. If the acceptable level is 0.5 ppm, would this fish be safe to eat? S: 1. ppm = 6 x 10-4 g x 106 1.6 x 103 g = 0.38 ppm

  16. Highland Science Department Concentration e.g. A 1.6 kg fish was found to contain 0.6 mg of mercury. If the acceptable level is 0.5 ppm, would this fish be safe to eat? S: 1. ppm = 6 x 10-4 g x 106 1.6 x 103 g = 0.38 ppm 2. yes, it's ok to eat the fish because its concentration is lower than 0.5 ppm

  17. Highland Science Department Concentration Molar Concentration: the number of moles of solute that can dissolve in 1 L of solution molar concentration = moles of solute solution volume (L) C = n V

  18. Highland Science Department Concentration e.g. 1. A solution contains 5.85 g of sodium chloride dissolved in 5000 mL of water. What is the molar concentration of the sodium chloride?

  19. Highland Science Department Concentration e.g. 1. A solution contains 5.85 g of sodium chloride dissolved in 5000 mL of water. What is the molar concentration of the sodium chloride? G: NaCl mass = 5.85 g volume = 5000 mL x = 5.00 L M.M. NaCl = 58.5 g/mol

  20. Highland Science Department Concentration e.g. 1. A solution contains 5.85 g of sodium chloride dissolved in 5000 mL of water. What is the molar concentration of the sodium chloride? G: NaCl mass = 5.85 g volume = 5000 mL x = 5.00 L M.M. NaCl = 58.5 g/mol U: molar concentration

  21. Highland Science Department Concentration e.g. 1. A solution contains 5.85 g of sodium chloride dissolved in 5000 mL of water. What is the molar concentration of the sodium chloride? n MM V S: mass  moles concentration

  22. Highland Science Department Concentration e.g. 1. A solution contains 5.85 g of sodium chloride dissolved in 5000 mL of water. What is the molar concentration of the sodium chloride? S: Conc = 5.85 g x x = 5.85 mol/L 58.5 x 5.00 = 0.02 mol/L

  23. Highland Science Department Concentration e.g. 2. What mass of potassium hydroxide is required to prepare 600 mL of a solution with a concentration of 0.225 mol/L?

  24. Highland Science Department Concentration e.g. 2. What mass of potassium hydroxide is required to prepare 600 mL of a solution with a concentration of 0.225 mol/L? G: conc KOH = 0.225 mol/L volume = 600 mL x = 0.600 L M.M. KOH = 56.1 g/mol

  25. Highland Science Department Concentration e.g. 2. What mass of potassium hydroxide is required to prepare 600 mL of a solution with a concentration of 0.225 mol/L? G: conc KOH = 0.225 mol/L volume = 600 mL x = 0.600 L M.M. KOH = 56.1 g/mol U: mass of KOH

  26. Highland Science Department Concentration e.g. 2. What mass of potassium hydroxide is required to prepare 600 mL of a solution with a concentration of 0.225 mol/L? n V MM S: concentration  moles  mass

  27. Highland Science Department Concentration e.g. 2. What mass of potassium hydroxide is required to prepare 600 mL of a solution with a concentration of 0.225 mol/L? S: KOH mass = 0.225 mol x x 1 L = 0.225 x 0.600 x 56.1 g = 7.57 g

  28. Highland Science Department Concentration e.g. 3. A solution containing 0.125 mol/L of MgCl2 is required for an experiment. If 87.8 g of solid MgCl2 is available, what is the maximum volume of solution that can be prepared?

  29. Highland Science Department Concentration e.g. 3. A solution containing 0.125 mol/L of MgCl2 is required for an experiment. If 87.8 g of solid MgCl2 is available, what is the maximum volume of solution that can be prepared? G: MgCl2 mass = 87.8 g concentration = 0.125 mol/L M.M. MgCl2 = 95.3g/mol

  30. Highland Science Department Concentration e.g. 3. A solution containing 0.125 mol/L of MgCl2 is required for an experiment. If 87.8 g of solid MgCl2 is available, what is the maximum volume of solution that can be prepared? G: MgCl2 mass = 87.8 g concentration = 0.125 mol/L M.M. MgCl2 = 95.3g/mol U: volume

  31. Highland Science Department Concentration e.g. 3. A solution containing 0.125 mol/L of MgCl2 is required for an experiment. If 87.8 g of solid MgCl2 is available, what is the maximum volume of solution that can be prepared? G: MgCl2 mass = 87.8 g concentration = 0.125 mol/L M.M. MgCl2 = 95.3g/mol U: volume n MM V S: mass  moles  volume

  32. Highland Science Department Concentration e.g. 3. A solution containing 0.125 mol/L of MgCl2 is required for an experiment. If 87.8 g of solid MgCl2 is available, what is the maximum volume of solution that can be prepared? S: volume = 87.8 g x x = 87.8 L 95.3 x 0.125 = 7.37 L

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