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Chemistry Week 25

Chemistry Week 25. Please get out your Classwork and a calculator!. March 6, 2013. AGENDA: 1 – Agenda/ Bell Ringer 2 – Review HW 3 – CN: Gram to Gram Stoichiometry 4 – Work Time. Today’s Goal:

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Chemistry Week 25

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  1. Chemistry Week 25 Please get out your Classwork and a calculator!

  2. March 6, 2013 AGENDA: 1 – Agenda/ Bell Ringer 2 – Review HW 3 – CN: Gram to Gram Stoichiometry 4– Work Time Today’s Goal: Students will be able to convert complete 3-step stoichiometry conversions between grams and grams. Homework • Gram to Gram Stoichiometry • Friday is the Last Day to make up last week’s quiz.

  3. Wednesday, March 6th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and grams. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10H2O Set-up the units for converting moles of O2 to grams of CO2. Moles O2 x ________ x _________ = grams CO2

  4. March 6, 2013 AGENDA: 1 – Agenda/ Bell Ringer 2 – Review HW 3 – CN: Gram to Gram Stoichiometry 4– Work Time Today’s Goal: Students will be able to convert complete 3-step stoichiometry conversions between grams and grams. Homework • Gram to Gram Stoichiometry • Friday is the Last Day to make up last week’s quiz.

  5. Wednesday, March 6th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and grams. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10H2O Set-up the units for converting moles of O2 to grams of CO2. Moles O2 x moles CO2 x molar mass CO2= gCO2 moles O2 1 mol CO2

  6. Obj: SWBAT complete 3-step stoichiometry conversions between grams and grams. Date: 3/6/2013 Balanced Chemical Equation: a A b B Coefficients = # moles of each compound Grams MolesMoles Grams A AB B ÷ Molar Mass of A x Molar Mass of B xb a

  7. 2 Mg + 1 O2 2MgO Grams A  Mole A  Mole B  Gram B How many grams of MgO would you form from 25 grams of Mg? • Calculate Molar Mass for both compounds in the problem. 2. Molar Mass Mg = 24.3 24.3 g 1mol 1. Molar Mass Mg = 24.3 O = + 16 40.3 g 1mol

  8. Practice Problem: Gram A  Mole A  Mole B  Gram B 2 Mg + 1 O2 2MgO Grams A  Mole A  Mole B  Gram B How many grams of MgO would you form from 25 gram of Mg? 2 molMgO 1 mol Mg 40.3 g MgO 25 g Mg x x = x 2 mol Mg 1molMgO 24.3g Mg 25 x 1 x 2 x 40.3 g MgO 24.3 x 2 x 1 2015 48.6 = 41.5 g MgO =

  9. Set-Up Help Balanced ChemEq: aA bB • Calculate the molar masses of both compounds in the problem • Convert: remember Given and Want Given(g) x1 molGivenx molWant x Mol.massWant = Mol.massGivenmolGiven 1 molWant • Multiply everything in numerator. • Multiply everything in the denominator • Divide Numerator by Denominator.

  10. Set-Up Help Balanced ChemEq: aA bB • Mole A Mole B  Gram B: Mole A xb Mole B x Molar Mass B = Gram B a Mole A 1 molB • Gram A  Mole A  Mole B Gram A x 1Mole Ax b Mole B= Mole B Molar Mass A amolA

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