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Chemistry Week 25

Chemistry Week 25. Please get out your Classwork and a calculator !. March 5, 2013. AGENDA: 1 – Agenda/ Bell Ringer 2 – CN: Mole to Gram Stoichiometry 3 – Work Time. Today’s Goal:

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Chemistry Week 25

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  1. Chemistry Week 25 Please get out your Classwork and a calculator!

  2. March 5, 2013 AGENDA: 1 – Agenda/ Bell Ringer 2– CN: Mole to Gram Stoichiometry 3 – Work Time Today’s Goal: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Homework • Mole to Gram Stoichiometry • Friday is the Last Day to make up last week’s quiz.

  3. Tuesday, March 5th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10 H2O How many moles of H2O will form if you react 20 moles of O2?

  4. 2MINUTES REMAINING…

  5. Tuesday, March 5th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10 H2O How many moles of H2O will form if you react 20 moles of O2?

  6. 1MINUTES REMAINING…

  7. Tuesday, March 5th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10 H2O How many moles of H2O will form if you react 20 moles of O2?

  8. 10 seconds Remaining…

  9. BELL-RINGER TIME IS UP!

  10. March 5, 2013 AGENDA: 1 – Agenda/ Bell Ringer 2– CN: Mole to Gram Stoichiometry 3 – Work Time Today’s Goal: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Homework • Mole to Gram Stoichiometry • Friday is the Last Day to make up last week’s quiz.

  11. Tuesday, March 5th Objective: Students will be able to convert complete 2-step stoichiometry conversions between grams and moles. Bell Ringer: 2 C4H10 + 13 O2 8 CO2 + 10 H2O How many moles of H2O will form if you react 20 moles of O2? mols H2O 20 molsO2 10 15.4 mols H2O = x mols O2 13

  12. Obj: SWBAT complete 2-step stoichiometry conversions between grams and moles. Date: 3/5/2013 Balanced Chemical Equation: a A b B Coefficients = # moles of each compound Grams MolesMoles Grams A AB B ÷ Molar Mass of A x Molar Mass of B xb a • xa • b x Molar Mass of A ÷ Molar Mass of B

  13. 2 Mg + 1 O2 2MgO Mole A  Mole B  Gram B How many grams of MgO would you form from 5 mol of Mg? 1. Molar Mass Mg = 24 O = + 16 40 g 1mol 2. Conversions 5 mol Mg x 2 mol MgO x 40 g MgO 2 mol Mg 1 mol MgO = 5 x 2 x 40 g MgO = 400 = 200 g MgO 2 2

  14. Practice Problem: Mole A  Mole B  Gram B 2 HCl 1 H2+ 1 Cl2 How many gram of H2will form from 14 moles of Cl2? Molar Mass H2 : H = 2 x 1.0 = 2.0 g/mol 1 mol H2 2.0 grams H2 1 mol H2 28 g H2 1 14mol Cl2 x x = 1 molCl2 = 28 g H2

  15. 2 Mg + 1 O2 2MgO Gram A  Mole A  Mole B How many moles of O2 must be present to react with 100 g of Mg? 1. Molar Mass Mg = 24.3 g mol 2. Conversions 100 g Mg x 1 mol Mg x 1 mol O2 24 g Mg 2 mol Mg = 100 x 1 x 1 mol O2 ≈ 2 mol O2 24 x 2

  16. Practice Problem: Gram A Mole A  Mole B 2 HCl 1 H2+ 1 Cl2 How many moles of Cl2will form from 40 grams of HCl? Molar Mass HCl : H = 1 x 1.0 = 1.0 Cl = 1 x 35.5 = 35.5 HCl = 36.5 g/mol 1 mol Cl2 1 molHCl 40 mol Cl2 73 40 g HCl x 2molHCl x = 36.5 g HCl = 0.55 mol Cl2

  17. Set-Up Help Balanced ChemEq: aA bB • Mole A Mole B  Gram B: Mole A xb Mole B x Molar Mass B = Gram B a Mole A 1 molB • Gram A  Mole A  Mole B Gram A x 1Mole Ax b Mole B= Mole B Molar Mass A amolA

  18. Problem Solving Decision Tree Read the problem If moles and grams If moles and particles Calculate Molar Mass If particles moles If moles  grams If grams moles If moles  particles Multiply by molar mass Divide by molar mass Multiply by 6.02 x 1023 Divide by 6.02 x 1023

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