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Contoh 1:

Contoh 1: Pembangkit polynomial suatu sandi siklis (7,4) adalah g(x) = x 3 + x 2 +1. Carilah kata sandi dari vektor data d=(1 1 1 0) dengan sandi siklis non sistematis , menggunakan c(x)=d(x) g(x) Penyelesaian :

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Contoh 1:

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  1. Contoh 1: Pembangkit polynomial suatusandisiklis (7,4) adalah g(x) = x3 + x2 +1. Carilahkatasandidarivektor data d=(1 1 1 0) dengansandisiklis non sistematis, menggunakan c(x)=d(x) g(x) Penyelesaian : jikasandi yang dibentuk non sistematis, yaitudenganmembentuksandidengan c(x_=d(x) g(x) dengan d(x) adalah polynomial pesan. Makauntukvektor data d=(d1,d2,d3,d4)=(1110) polynomial sandinyaadalah : c(x) = (d(x) g(x) = (x3 + x2 + x (x3 + x2 + 1) = x6 + (1+1)x5 + (1+1)x4 + (1+1)x3 +x2 + x : koefadalahoperasi XOR = X6 + X2 +X = X6 + (0) X5 + (0) X4 + (0) X3 + X2 + X + 0 Mengahasilkanvektorsandic=(10000110)

  2. >> d=[1 1 1 0] • d = • 1 1 1 0 • >> g=[1 1 0 1] • g = • 1 1 0 1 >> c=conv (d , g ) • c = • 1 2 2 2 1 1 0 >> kode = mod ( c , 2 ) % hasilpengkodean • kode = • 1 0 0 0 1 1 0

  3. n=7 ; k=4 ; d= [0 1 1 1]% untuksektor data d=1110 code = encode( d, n , k, ‘cyclic’)

  4. d = • 0 1 1 1 • code = • 0 • 1 • 0 • 0 • 1 • 1 • 1

  5. Catatan : untukmengetahui generator pembangkitsiklis (7,4) >> g =cyclpoly ( 7, 4) g = 1 0 1 1 >> gfpretty (g) 1 + x2 + x3

  6. Tugas : • Pembangkitpolinomialsuatusandisiklis (7,4) adalah g(x) = x3+ x2 + 1 (g=1101). Carilahkatasandidarivektor data d1=(1111), d2= (1110), d3= (1101), d4= (1100), d5= (1011), d6= (1010), d7= (1001), d8= (1000), d9= (0111), d10= (0110), d11= (0101), d12= (0100), d13= (0011), d14= (0010), d15= (0001).

  7. Pembangkitpolinomialsuatusandisiklis ( 7,4 ) adalah g(x) = x3+ x2 + 1. carilahkatasansidari vektor data d1=(1111), d2=(1110), d3=(1101), d4=(1100), d5=(1011), d6=(1010), d7=(1001), d8=(1000), d9=(0111), d10=(0110), d11=(0101), d12=(1100), d13=(0011), d14=(0010), d15=(0001), d16=(0000). dengansandisiklissistematis.

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