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During chemical changes matter cannot be created or destroyed. It is merely rearranged. Example

Balancing Equations. O atom. H atom. During chemical changes matter cannot be created or destroyed. It is merely rearranged. Example hydrogen + oxygen =====> water 2 H 2 + O 2 ====> 2 H 2 O. Notice there are the same number and kinds of atoms on both sides of the equation.

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During chemical changes matter cannot be created or destroyed. It is merely rearranged. Example

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  1. Balancing Equations O atom H atom During chemical changes matter cannot be created or destroyed. It is merely rearranged. Example hydrogen + oxygen =====> water 2H2 + O2 ====> 2 H2O

  2. Notice there are the same number and kinds of atoms on both sides of the equation. O atom H atom 2H2 + O2 ====> 2 H2O

  3. This principal must be followed when writing chemical equations. Here are some examples: hydrogen + iodine ===> hydrogen iodide H2 + I2=====> HI 2 Products Reactants How can this equation be balanced?

  4. Another example is: 2 Products Reactants carbon tetrachloride carbon + chlorine CCl4 C + Cl2 How can this equation be balanced?

  5. Another example is: 2 2 Products Reactants sulfur dioxide sulfur trioxide + oxygen SO3 SO2 + O2 How can this equation be balanced?

  6. Rules for Balancing Equations 1. Make sure all formulae are correct 2. Balance the elements in the fewest # of compounds 1st. 3. Always work from a partly balanced formula to one that has not yet been balanced 4. If in the final stages of balancing, you end up with an odd # of atoms on one side of the equation and an even # of atoms on the other side, double everything balanced.

  7. AlOHOHOH AlOHOHOH AlOHOHOH AlOHOHOH Products Reactants Al4C3+ H2O --> CH4 + Al(OH)3 12 3 4 Al Al Al Al C C C H2O H2O H2O H2O H2O H2O H2O H2O H2O H2O H2O H2O CH4 CH4 CH4

  8. Balance the Following Equations CS2 + Cl2 --> CCl4 + SCl2 Al + Fe2O3 ---> Al2O3 + Fe Mg3N2 + H2O---> NH3 + MgO C3H8 + O2 ---> H2O + CO2

  9. 4 CS2 + Cl2 --> CCl4+ SCl2 2 Balance S first 2 S’s on the left Balance Cl next 8 Cl on the right

  10. Al + Fe2O3 ---> Al2O3 + Fe 2 2 Balance Fe first 2 Fe’s on the left Balance Al next 2 Al on the right

  11. 3 3 2 Mg3N2 + H2O---> NH3 + MgO Balance Mg first 3 Mg’s on the left Balance O next 3O on the right Balance H next 6 H’s on the left

  12. 5 4 C3H8 + O2 --> CO2+ H2O 3 Balance C first 3 C’s on the left Balance H next since O is found in 3 places 8 H’s on the left Balance O last 6 O’s in CO2 and 4 O’s in H2O total of 10 O’s on the right

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