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The year-long Algebra I course segmented into nine units. Our focus is within Unit 4.0.

The year-long Algebra I course segmented into nine units. Our focus is within Unit 4.0. Course Unit. Three Major Components of Unit. Our line-graphing standard for the focus of instruction. Our line-graphing standard for the focus of instruction. Terminal Objectives.

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The year-long Algebra I course segmented into nine units. Our focus is within Unit 4.0.

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  1. The year-long Algebra I course segmented into nine units. Our focus is within Unit 4.0.

  2. Course Unit Three Major Components of Unit Our line-graphing standard for the focus of instruction

  3. Our line-graphing standard for the focus of instruction Terminal Objectives

  4. Terminal Objective (4, 4) (2, 2) Enabling Objective 1 Enabling Objective 2 Enabling Objective 3 y = -3x +8 (4, 4) x y (2, 2) 1 2 3 4 5 2 1 4

  5. Terminal Objective If y = mx + b , then y = 4/3x - 4 Enabling Objective 1 Enabling Objective 2 Enabling Objective 3 y = -2x + 5 “-2 (m) is the slope of this line equation. When m < 0 the slope is negative. Therefore, this line has a negative slope.”

  6. Terminal Objective Enabling Objective 1 Enabling Objective 2 Enabling Objective 3 Enabling Objective 4 y = mx + b m = -2 b = 5 y = -2x + 5 slope y-intercept Let x = 0 m < 0 = negative slope m > 0 = positive slope • Slope is the measure of steepness of a line • Slope

  7. Given: (2, 3) and (6, 4) Terminal Objective So, Enabling Objective 2 Enabling Objective 3 Enabling Objective 4 Enabling Objective 1 Therefore, y = 1/4 x + 5/2 (x + 3) ¾ = (y + 2)(x + 3) y = ½ x + 5 and y = 2x - 5 (x + 3) “The slopes are not the same so the lines are not parallel. Both lines have unknown x and y values because the lines are infinite.” 4(3x + 9) = (y + 2)4 4 y –intercept = ¼ y = ¾ x + ¼

  8. Terminal Objective • I see that the slopes of the parallel lines is -1 • My two points are (-2, 2) • I can find the y-intercept as 2= (-1)(-2) +b = 0 • Therefore y = -x + 0 Enabling Objective 1 Enabling Objective 2 Enabling Objective 3 Enabling Objective 4 y = 2x – 5 and y = 2x + 4 “ The slopes are the same so the lines are parallel. The y-intercepts are different otherwise the lines would be the same line.” “These lines are dependent because their points are on the same line.”

  9. Terminal Objective Enabling Objective 1 Enabling Objective 2 Enabling Objective 3 Enabling Objective 4 5x+4y-20=0 5x+4y=20x intercept occurs when y=05x=20x=44 is the x intercept.4x+3y-12=03y=12-4xy=4-4x/3-4/3 is the slope of the line.The slope of a line that is perpendicular is the negative reciprocal of the slope which in this case is 3/4 “A line is perpendicular to another if they meet at 90 degrees.” 5x+4y-20=0 5x+4y=205x=20x=44x+3y-12=03y=12-4xy=4-4x/3-4/3 is the slope of the line. “The slope of a line that is perpendicular is the negative reciprocal of the slope.”

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