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Contributing Project Pg.526, 532, 542, 548 and 549

Contributing Project Pg.526, 532, 542, 548 and 549. By : Ahmad Bassam Class: 7D Date: April 30 – May 1. Pg. 526. Questions: 33-34. Question 33:. Solution: 4 + 2 + 2 = 8 6 + 2 + 2 = 10 0.5(b1+b2)*h=area Side: (4+8)/2)*2=12 in2

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Contributing Project Pg.526, 532, 542, 548 and 549

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  1. Contributing ProjectPg.526, 532, 542, 548 and 549 By : Ahmad Bassam Class: 7D Date: April 30 – May 1

  2. Pg. 526 Questions: 33-34

  3. Question 33: • Solution: 4+2+2=86+2+2=10 0.5(b1+b2)*h=area Side: (4+8)/2)*2=12 in2 Bottom: (6+10)/2)*2=16 in2 Ratio: 16 in2 for the bottom: 12 in2 for the side 2 8 4 2 6 10

  4. Question 34: • 2n*2n=4n Area is 4n 2n 2n 2n 2n

  5. Pg.532 Questions 28, 29, and 33

  6. Question 28 • To solve this problem do the opposite: • 1473/3.14=469.10 • Square root of 469.10= 21.65 • 2.65 *2=43.3 is the diameter

  7. Question 29 • 58 is the length of the arm which is the radius • First find the circumference: d*pie=c • (58+58)*3.14= 364.24 • Then multiply it by the number of laps per minute: 50 • 364.2412*50= 18,212 round= 18,200ft

  8. Question: 33 • A) 12*12*3.14=452 inch • B)7850

  9. Pg.542 Question 12 and 17

  10. Question 12: • The Surface Area: 2*pie*r*r+2*pie*r*h=318.71cm

  11. Question 17: • A) The area will get 8 times bigger when height and radius are doubled. • B) The circumference will be double when height and radius are doubled. • C)It will be quadrupled when height and radius are doubled.

  12. Pg.548 Question 28

  13. Question 28: • Surface area of a pyramid is: the area of each triangle times 4 plus the area of base • The triangles:.5*74*48=1776*4=7,104 • The base: 74*74=5476 • Add them together: 7104+5476= 12,580 ft2

  14. Pg.549 Question 30

  15. Question 30: • A)Don’t know • B) Don’t know • I didn’t understand them

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