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Example: Structural Analysis of a Bipolar Plate in a Fuel Cell Stack. Bipolar Plate – Problem Definition. Introduction. A unit fuel cell produces a limited voltage. In order to produce a higher voltage, a number of unit cells are connected in a series - a fuel cell stack.
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Example:Structural Analysis of aBipolar Plate in a Fuel Cell Stack
Bipolar Plate – Problem Definition Introduction • A unit fuel cell produces a limited voltage. In order to produce a higher voltage, a number of unit cells are connected in a series - a fuel cell stack. • Each unit cell consist of a bipolar plate, an anode, a polymer membrane, and a cathode, as can be seen in the figure below: Fuel cell stack Membrane Bipolar plate Anode Cathode
Bipolar Plate – Problem Definition Introduction • We will investigate how the forces from the tie rods and the thermal loads affect the bipolar plate. Heat sources Holes for gas feeding Holes for tie rods Heat sources
Bipolar Plate – Problem Definition Simplified forces that affects the plate F2 F2 F1 F1
Bipolar Plate – Problem Definition Symmetry conditions Thickness = t 1/4 1/8 1/2 Thickness = t/2 =0.005 m
Bipolar Plate – Problem Definition Modeling procedure • Select the 3D Heat Transfer (COMSOL Multiphysics) and the 3D Solid (Structural Mechanics Module) application modes. • Draw the geometry with the COMSOL Multiphysics built-in CAD-tools. • Set properties for the heat transfer problem. • Solve the heat transfer problem. • Set properties for the structural problem. • Solve the one-way coupled heat transfer and structural problem. • Visualize the results.
Bipolar Plate – Problem Definition Draw the geometry Draw the geometry in a 2D workplane... y x …and extrude the objects 0.005 m in the z-direction.
Bipolar Plate – Mesh Mesh the geometry
Bipolar Plate – Problem Definition Heat Transfer - boundary conditions h=10 Tinf=273+20 Insulation/symmetry h=50 Tinf=273+80 q=0 h=0
Bipolar Plate – Problem Definition Heat Transfer - subdomain settings Aluminum Q=2/((pi*0.005^2*0.005)/2) Titanium Titanium
Bipolar Plate – Results Solution to the heat transfer problem
Bipolar Plate – Problem Definition SME : Solid - boundary conditions z y x No displacement in x No displacement in y No displacement in z Applied load in z= -10·9.82·1e10 Applied load in z= -80·9.82·1e10
Bipolar Plate – Problem Definition SME : Solid - subdomain settings Titanium Not Active Titanium
Bipolar Plate – Results No thermal effects Total displacement Max = 0.00379 mm von Mises stresses Max = 9.35 MPa
Bipolar Plate – Results Solution and post-processing von Mises stresses Max = 76 MPa Total displacement Max = 0.376 mm