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Today's Agenda .th 1/6/11. Recall – Names of compounds and molar masses from “the chart” Get your comp books out before the bell rings Stoichiomtry Calculations involving Mass Problems 1 + 2 on Stoichiomtry worksheet Homework: problems 3 + 4 on Stoichiomtry worksheet in your notebooks.
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Today's Agenda .th 1/6/11 • Recall – Names of compounds and molar masses from “the chart” • Get your comp books out before the bell rings • Stoichiomtry Calculations involving Mass • Problems 1 + 2 on Stoichiomtry worksheet • Homework: problems 3 + 4 on Stoichiomtry worksheet in your notebooks. http://teachers.yourhomework.com/blowe/ 1
Quiz Reminder • Quiz next Tuesday 1/11/11
Recall Write the Chemical symbol for the following: • Silver Sulfide • Calcium Phosphate • Magnesium Chloride • Palladium (IV) Fluoride • Chromium (III) Nitride • Potassium Oxalate • Lead (IV) Iodide Ag1+ Ca2+ Mg2+ Pd4+ Cr3+ K1+ Pb4+ S2- P3- Cl1- F1- N3- C2O42- I1- Ag2S Ca3P2 MgCl2 PbF4 CrN K2C2O4 PbI4 http://teachers.yourhomework.com/blowe/ 3
Recall 2 Find the molar mass for the following: • Ag2S • Ca3P2 • MgCl2 • PbF4 • CrN • K2C2O4 • PbI4 2(107.9) + 32.06 = 3(40.08) + 2(30.97) = 24.31 + 2(35.45) = 106.4 + 4(19.00) = 52 + 14.01 = 2(39.10)+2(12.01)+4(16)= 204.4 + 4(126.9)= 247.86 g/mol 182.18 g/mol 95.21 g/mol 182.4 g/mol 66.01 g/mol 166.22 g/mol 712.00 g/mol http://teachers.yourhomework.com/blowe/ 4
Example 1 • Sodium fluoride is reacted with calcium nitrate to produce sodium nitrate and calcium fluoride. • If 84 g of sodium fluoride are present, what would the mass of calcium nitrate be required in the reaction? • What would be the mass of the two products?
Example 1 2NaF + Ca(NO3)2 2NaNO3 + CaF2 84 g NaF NaF Ca(NO3)2NaNO3 CaF2 Now use mole ratios to find the moles of the other cheicals 2 x 2 x 2 x 1 x 164.1 = 164.1 2 x 85 = 170 1 x 78.08 = 78.08 84 22.99 + 14.01 + 3(16.00) = 85 40.08+ 2(14.01)+ 6(16.00) =164.1 22.99 + 19 = 41.99 40.08 + 2(19.00) = 78.08
Example 1 • Final answers are: • 164.1 g of Ca(NO3)2 • 170 g of NaNO3 • 78.08 g of CaF2
Problem 1 on Stoichiomtry WS 4Na + O2 2Na2O 92.0 g of O2 NaO2Na2O Now use mole ratios to find the moles of the other cheicals 2.87 x 2.87 x 11.5 x 22.99 = 264.39 5.75 x 61.98 = 356.39 92.0 2(22.99) + 16.00 =61.98 2(16.00)=32.00 22.99
Problem 1 on Stoichiomtry WS • Final answers are: • 264.39 g of Na • 92g of O2 • 356.39 g of Na2O
Problem 2 on Stoichiomtry WS 2AgNO3 + Zn 2Ag + Zn(NO3)2 340 g of Ag AgNO3Zn Ag Zn(NO3)2 Now use mole ratios to find the moles of the other cheicals 3.2 3.2 3.2 3.2 x 49.08 = 543.71 1.6 x 65.38 = 104.608 1.6 x 189.4 = 303.04 340 107.9 + 14.01+ 3(16.00) =169.91 65.38 + 2(14.01)+ 6(16.00) =189.4 65.38 107.9
Problem 2 on Stoichiomtry WS • Final answers are: • 543.71g of AgNO3 • 104.608g of Zn • 340g of Ag • 303.04g of Zn(NO3)2
Homework Complete problems 3+4 from the Stoichometry worksheet in your comp notebook for a notebook stamp You must include the table and correct numbers for credit http://teachers.yourhomework.com/blowe/ 12