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Today's Agenda .m 1/10/11. Recall Get your comp books out before the bell rings Correct problems 5 + 6 from the Stoichiomtry worksheet in your notebook Homework: Prepare for Quiz tomorrow. http://teachers.yourhomework.com/blowe/. 1. Recall. Find the # of moles of

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teachers.yourhomework/blowe/

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  1. Today's Agenda .m 1/10/11 • Recall • Get your comp books out before the bell rings • Correct problems 5 + 6 from the Stoichiomtry worksheet in your notebook • Homework: Prepare for Quiz tomorrow http://teachers.yourhomework.com/blowe/ 1

  2. Recall Find the # of moles of • 1 g of Carbon dioxide CO2 • 1 g of Carbon monoxide CO Find the mass (in g) of • 1 mole Hydrogen chloride HCl • 1 mole Potassium nitrate KNO3Hint: Find the Molar Mass of all Compounds 11/18/10 http://teachers.yourhomework.com/blowe/ 2

  3. Recall 2 Write out the covalent compounds for the following: • Dinitrogen trioxide • Diphosphorus tetroxide • Sulfur trioxide • Iodine pentafluoride • Silicon tetrachloride • Phosphorus trichloride N2O3 P2O4 SO3 IF5 SiCl4 PCl3 Notice how there was no charges, that’s because these are covalent bonds and not ionic. 11/30/10 http://teachers.yourhomework.com/blowe/ 3

  4. Quiz Reminder • Quiz next is tomorrow 1/11/11 • Open notes/book • No worksheets

  5. Problem 5a on Stoichiomtry WS (NH4)2SO4 + 2NaNO3 2NH4NO3 + Na2SO4 2.64 g of (NH4)2SO4 (NH4)2SO4 NaNO3NH4NO3 Na2SO4 .019 .019 .019 .04 x 85 = 3.31 .4 x 80.052 = 3.19 .19 x 142.04 = 2.69 2.64 2(14.01)+ 8(1.008)+ 32.06+ 4(16) =132.144 2(14.01)+ 4(1.009)+ 3(16) =80.052 2(22.99)+ 32.06+ 4(16) =142.04 22.99+ 14.01+ =85

  6. Problem 5b on Stoichiomtry WS (NH4)2SO4 + 2NaNO3 2NH4NO3 + Na2SO4 170 g of NaNO3 (NH4)2SO4 NaNO3NH4NO3 Na2SO4 2 2 2 1 x 132.144 = 132 1 x 142.04 = 142 2 x 80.052 = 160 170 2(14.01)+ 8(1.008)+ 32.06+ 4(16) =132.144 2(14.01)+ 4(1.009)+ 3(16) =80.052 2(22.99)+ 32.06+ 4(16) =142.04 22.99+ 14.01+ =85

  7. Problem 6a on Stoichiomtry WS 2AlCl3 + 3Pb(NO3)2 2Al(NO3)3 + 3PbCl2 26.7 g of AlCl3 AlCl3 Pb(NO3)2Al(NO3)3 PbCl2 .2 .2 .2 .3 x 331.22 =99.36 .2 x 213.01 = 42.602 .3 x 278.1 = 83.43 26.7 207.2+ 2(14.01)+ 6(16) =331.22 26.98 3(14.01) 9(16) =213.01 26.98+ 3(35.45) =133.33 207.2 2(35.45) =278.1

  8. Problem 6b on Stoichiomtry WS 2AlCl3 + 3Pb(NO3)2 2Al(NO3)3 + 3PbCl2 8.28 g of Pb(NO3)2 AlCl3 Pb(NO3)2Al(NO3)3 PbCl2 .024 .024 .024 .016 x 133.33 =2.123 .016 x 213.01 = 3.4 .024 x 278.1 = 6.67 8.28 207.2+ 2(14.01)+ 6(16) =331.22 26.98 3(14.01) 9(16) =213.01 26.98+ 3(35.45) =133.33 207.2 2(35.45) =278.1

  9. The Quiz • 2 Stoichiomtry problems • One where the chemical equation is given • One where you have to determine the chemical equations

  10. Homework Review and study for the quiz tomorrow http://teachers.yourhomework.com/blowe/ 10

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