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Unit 3 Test (Part 2) Review

Unit 3 Test (Part 2) Review. Stoichiometry. Balancing Equations. Balance the following chemical equation: ____ Ag 2 O  ____ Ag + ____O 2. Balancing Equations. Balance the following chemical equation: 2 Ag 2 O  4 Ag + O 2. Identifying Reaction Types.

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Unit 3 Test (Part 2) Review

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  1. Unit 3 Test (Part 2) Review Stoichiometry

  2. Balancing Equations Balance the following chemical equation: ____ Ag2O  ____ Ag + ____O2

  3. Balancing Equations Balance the following chemical equation: 2 Ag2O 4 Ag + O2

  4. Identifying Reaction Types C6H12 + 9 O2 6 CO2 + 6 H2O Reaction Type: _________________

  5. Identifying Reaction Types C6H12 + 9 O2 6 CO2 + 6 H2O Reaction Type: combustion

  6. Balancing Equations Balance the following chemical equation: __ AlBr3 + __ K2SO4 __ KBr + __ Al2(SO4)3

  7. Balancing Equations Balance the following chemical equation: 2 AlBr3 + 3 K2SO46 KBr + Al2(SO4)3

  8. Stoichiometry: Limiting Reactant SeCl6 + O2 SeO2 + 3 Cl2 How many grams of chlorine can be produced from the reaction of 13.7 grams of SeCl6 and 13.7 grams of oxygen? Also, what is the limiting reactant?

  9. Stoichiometry: Limiting Reactant SeCl6 + O2 SeO2 + 3 Cl2 How many grams of chlorine can be produced from the reaction of 13.7 grams of SeCl6 and 13.7 grams of oxygen? Also, what is the limiting reactant? 9.99 g Cl2 (Limiting reactant = SeCl6)

  10. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many grams of water can be produced from 0.910 moles of C6H12?

  11. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many grams of water can be produced from 0.910 moles of C6H12? 98.4 g H2O

  12. Balancing Equations Balance the following chemical equation: __ HCN + __ CuSO4 __ H2SO4 + __ Cu(CN)2

  13. Balancing Equations Balance the following chemical equation: 2 HCN + CuSO4 H2SO4 + Cu(CN)2

  14. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many molecules of water can be produced from 2.49 moles of oxygen?

  15. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many molecules of water can be produced from 2.49 moles of oxygen? 1.00 x 1024 molecules H2O

  16. Balancing Equations Balance the following chemical equation: __ C8H18 + __ O2 __ CO2 + __ H2O

  17. Balancing Equations Balance the following chemical equation: 2 C8H18 + 25 O216 CO2 + 18 H2O

  18. Identifying Reaction Types Na3PO4 + 3 KOH  3 NaOH + K3PO4 Reaction Type: __________________

  19. Identifying Reaction Types Na3PO4 + 3 KOH  3 NaOH + K3PO4 Reaction Type: double replacement

  20. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many grams of carbon dioxide can be produced from 11.2 grams of C6H12?

  21. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many grams of carbon dioxide can be produced from 11.2 grams of C6H12? 35.1 g CO2

  22. Balancing Equations Balance the following chemical equation: ___ Na + ___ H2O  ___ NaOH + ___H2

  23. Balancing Equations Balance the following chemical equation: 2 Na + 2 H2O 2 NaOH + H2

  24. Identifying Reaction Types P4 + 3 O2 2 P2O3 Reaction Type: __________________

  25. Identifying Reaction Types P4 + 3 O2 2 P2O3 Reaction Type: synthesis

  26. Stoichiometry: Limiting Reactant SeCl6 + O2 SeO2 + 3 Cl2 If the actual yield of this reaction was 4.6 grams of chlorine, what is the percent yield?

  27. Stoichiometry: Limiting Reactant SeCl6 + O2 SeO2 + 3 Cl2 If the actual yield of this reaction was 4.6 grams of chlorine, what is the percent yield? Percent Yield = 46.0%

  28. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many moles of carbon dioxide can be produced from 3.37 moles of oxygen?

  29. Stoichiometry C6H12 + 9 O2 6 CO2 + 6 H2O How many moles of carbon dioxide can be produced from 3.37 moles of oxygen? 2.25 mol CO2

  30. Identifying Reaction Types 2 AgNO3 + Cu  Cu(NO3)2 + 2 Ag Reaction Type: _________________

  31. Identifying Reaction Types 2 AgNO3 + Cu  Cu(NO3)2 + 2 Ag Reaction Type: single replacement

  32. Stoichiometry: Limiting Reactant 2 AgNO3 + Cu  2 Ag + Cu(NO3)2 How many grams of copper (II) nitrate can be produced from the reaction of 0.203 moles of Cu and 0.450 moles of AgNO3 Also, what is the limiting reactant?

  33. Stoichiometry: Limiting Reactant 2 AgNO3 + Cu  2 Ag + Cu(NO3)2 How many grams of copper (II) nitrate can be produced from the reaction of 0.203 moles of Cu and 0.450 moles of AgNO3 Also, what is the limiting reactant? 38.1 g Cu(NO3)2 Limiting Reactant = AgNO3

  34. Stoichiometry: Limiting Reactant 2 AgNO3 + Cu  2 Ag + Cu(NO3)2 If the actual yield of the reaction was 4.44 grams of copper (II) nitrate, what is the percent yield?

  35. Stoichiometry: Limiting Reactant 2 AgNO3 + Cu  2 Ag + Cu(NO3)2 If the actual yield of the reaction was 4.44 grams of copper (II) nitrate, what is the percent yield? Percent Yield = 11.7% (Yikes!)

  36. Identifying Reaction Types CaCO3 CaO + CO2 Reaction Type: _________________

  37. Identifying Reaction Types CaCO3 CaO + CO2 Reaction Type: decomposition

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