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Ionic Compounds with Polyatomic Ions

Ionic Compounds with Polyatomic Ions. Polyatomic Ions. A group of atoms with an overall charge. NH 4 + ammonium OH - hydroxide NO 3 - nitr ate NO 2 - nitr ite CO 3 2- Carbonate HCO 3 - hydrogen carbonate (bicarbonate). More Polyatomic Ions.

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Ionic Compounds with Polyatomic Ions

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  1. Ionic Compounds with Polyatomic Ions

  2. Polyatomic Ions A group of atoms with an overall charge. NH4+ ammonium OH- hydroxide NO3- nitrate NO2- nitrite CO32- Carbonate HCO3- hydrogen carbonate (bicarbonate)

  3. More Polyatomic Ions ite means one less oxygen is present, charge remains the same SO42- sulfate SO32- sulfite Hydrogen or Bi means you add a Hydrogen and reduce the charge by one HSO4-hydrogen sulfate HSO3- hydrogen sulfite PhosphatePO43- phosphite PO33- HPO42-Hydrogen Phosphate H2PO4-dihydrogen phosphate

  4. Naming Ionic Compounds with Polyatomic Ions or Ternary Compounds • Contain at least 3 elements • Name the nonmetals as a polyatomic ion • Examples: NaNO3Sodium nitrate K2SO4Potassium sulfate Al(HCO3)3Aluminumbicarbonate or Aluminumhydrogen carbonate

  5. Learning Check Match each set with the correct name: A.Na2CO3 1) magnesium sulfite MgSO3 2) magnesium sulfate MgSO4 3) sodium carbonate B. Ca(HCO3)2 1) calcium carbonate CaCO3 2) calcium phosphate Ca3(PO4)2 3) calcium bicarbonate

  6. Solution A.Na2CO3 3) sodium carbonate MgSO3 1) magnesium sulfite MgSO4 2) magnesium sulfate B. Ca(HCO3)2 3) calcium bicarbonate CaCO3 1) calcium carbonate Ca3(PO4)2 2) calcium phosphate

  7. Learning Check A. aluminum nitrate 1) AlNO3 2) Al(NO)3 3) Al(NO3)3 B. copper(II) nitrate 1) CuNO3 2) Cu(NO3)2 3) Cu2(NO3) C. Iron (III) hydroxide 1) FeOH 2) Fe3OH 3) Fe(OH)3 D. Tin(IV) hydroxide 1) Sn(OH)4 2) Sn(OH)2 3) Sn4(OH)

  8. Solution A. aluminum nitrate 3) Al(NO3)3 B. copper(II) nitrate 2) Cu(NO3)2 C. Iron (III) hydroxide 3) Fe(OH)3 D. Tin(IV) hydroxide 1) Sn(OH)4

  9. Notice • When formulas are formed, the number of Oxygens are NOT changed. • Sulfate has 4 Oxygens and is written SO4 if there is one, two or five present. • Number of SO4 ‘s present is shown by placing the Polyatomic in parenthesis and the amount is placed outside • 2 Sulfates would be written as (SO4)2

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