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Everyday Mathematics Family Night

Everyday Mathematics Family Night. September 22, 2010. Background. Developed by the University of Chicago School Mathematics Project Based on research about how students learn and develop mathematical power Provides the broad mathematical background needed in the 21 st century.

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Everyday Mathematics Family Night

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  1. Everyday MathematicsFamily Night September 22, 2010

  2. Background • Developed by the University of Chicago School Mathematics Project • Based on research about how students learn and develop mathematical power • Provides the broad mathematical background needed in the 21st century

  3. You can expect to see… • …a problem-solving approach based on everyday situations • …an instructional approach that revisits concepts regularly • …frequent practice of basic skills, often through games • …lessons based on activities and discussion, not a textbook • …mathematical content that goes beyond basic arithmetic

  4. A Spiral Approach to Mathematics • The program moves briskly and revisits key ideas and skills in slightly different contexts throughout the year. • Multiple exposure to topics ensures solid comprehension. • Strands are woven together-no strand is in danger of being left out.

  5. More Spiraling… • Mastery is developed over time. The Content by Strand Poster depicts the interwoven design. • Homework problems will have familiar formats, but different levels of difficulty.

  6. Everyday Mathematics Website • Each student will receive login for home access. (available from your child’s teacher) • Website contents: games and student reference book (SRB) • http://www.everydaymathonline.com

  7. Something to think about… • “Even though it doesn’t look quite like what you did when you went to school, yes, this is really good, solid mathematics.”-2001 Education Development Center Inc.

  8. Focus Algorithms Algorithm slides created by Rina Iati, South Western School District, Hanover, PA

  9. Partial Sums An Addition Algorithm

  10. 268 Add the hundreds (200 + 400) + 483 + 11 Add the partial sums (600 + 140 + 11) Partial Sums 600 Add the tens (60 +80) 140 Add the ones (8 + 3) 751

  11. 785 Add the hundreds (700 + 600) + 641 + 6 Add the partial sums (1300 + 120 + 6) Let's try another one 1300 Add the tens (80 +40) 120 Add the ones (5 + 1) 1426

  12. 329 + 989 + 18 Do this one on your own Let's see if you're right. 1200 100 1318 Well Done!

  13. Trade-First Subtraction An alternative subtraction algorithm

  14. 12 8 12 In order to subtract, the top number must be larger than the bottom number 2 9 3 2 - 3 5 6 To make the top number in the ones column larger than the bottom number, borrow 1 ten. The top number become 12 and the top number in the tens column becomes 2. 5 7 6 To make the top number in the tens column larger than the bottom number, borrow 1 hundred. The top number in the tens column becomes 12 and the top number in the hundreds column becomes 8. Now subtract column by column in any order

  15. 11 Let’s try another one together 6 15 1 7 2 5 - 4 9 8 To make the top number in the ones column larger than the bottom number, borrow 1 ten. The top number become 15 and the top number in the tens column becomes 1. 2 2 7 To make the top number in the tens column larger than the bottom number, borrow 1 hundred. The top number in the tens column becomes 11 and the top number in the hundreds column becomes 6. Now subtract column by column in any order

  16. 13 8 12 3 9 4 2 - 2 8 7 Now, do this one on your own. 6 5 5 Let's see if you're right. Congratulations!

  17. 9 Last one! This one is tricky! 6 13 10 7 0 3 - 4 6 9 2 3 4 Oh, no! What do we do now? Let's trade from the hundreds column Let's see if you're right. Congratulations!

  18. Partial Products Algorithm for Multiplication

  19. + To find 67 x 53, think of 67 as 60 + 7 and 53 as 50 + 3. Then multiply each part of one sum by each part of the other, and add the results 6 7 X 5 3 3,000 Calculate 50 X 60 350 Calculate 50 X 7 180 Calculate 3 X 60 21 Calculate 3 X 7 3,551 Add the results

  20. + Let’s try another one. 1 4 X 2 3 200 Calculate 10 X 20 80 Calculate 20 X 4 30 Calculate 3 X 10 12 Calculate 3 X 4 322 Add the results

  21. + Do this one on your own. 3 8 Let’s see if you’re right. X 7 9 2, 100 Calculate 30 X 70 560 Calculate 70 X 8 270 Calculate 9 X 30 72 Calculate 9 X 8 3002 Add the results

  22. Partial Quotients A Division Algorithm

  23. 12 158 The Partial Quotients Algorithm uses a series of “at least, but less than” estimates of how many b’s in a. You might begin with multiples of 10 – they’re easiest. 13 R2 There are at least ten 12’s in 158 (10 x 12=120), but fewer than twenty. (20 x 12 = 240) - 120 10 – 1st guess Subtract 38 There are more than three (3 x 12 = 36), but fewer than four (4 x 12 = 48). Record 3 as the next guess 3 – 2nd guess - 36 Subtract 2 13 Sum of guesses Since 2 is less than 12, you can stop estimating. The final result is the sum of the guesses (10 + 3 = 13) plus what is left over (remainder of 2 )

  24. 36 7,891 Let’s try another one 219 R7 - 3,600 100 – 1st guess Subtract 4,291 - 3,600 100 – 2nd guess Subtract 691 - 360 10 – 3rd guess 331 - 324 9 – 4th guess 7 219 R7 Sum of guesses

  25. 43 8,572 Now do this one on your own. 199 R 15 - 4,300 100 – 1st guess Subtract 4272 -3870 90 – 2nd guess Subtract 402 - 301 7 – 3rd guess 101 - 86 2 – 4th guess 199 R 15 Sum of guesses 15

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