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Vo 2 máx. = [(Distancia*2,2 ) – (504)/45 ) ] * (Peso/1000)

Vo 2 máx. = [(Distancia*2,2 ) – (504)/45 ) ] * (Peso/1000). Ejemplo : Calcular el Vo 2 max . - Si el lobito Inmaculado recorre 1200 metros en 5 minutos y su peso corporal equivale a 60 k. Vo 2 max . = Volumen máximo de oxígeno. Distancia = Distancia recorrida en 5 minutos.

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Vo 2 máx. = [(Distancia*2,2 ) – (504)/45 ) ] * (Peso/1000)

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  1. Vo2 máx. =[(Distancia*2,2 )– (504)/45 ) ] * (Peso/1000) Ejemplo : Calcular el Vo2max. - Si el lobito Inmaculado recorre 1200 metros en 5 minutos y su peso corporal equivale a 60 k. Vo2max. = Volumen máximo de oxígeno. Distancia = Distancia recorrida en 5 minutos. Peso= Peso corporal. Reemplazando en la formula:

  2. REEMPLAZANDO EN LA FORMULA: Vo2max. = [ (1200*2,2 )– 504/45 ] Vo2max. = [2640 -504/45] Vo2max. =2136/45 Vo2max. = 47.46 (ml/kg/min)

  3. Para convertir el Vo2 a litros por minuto, multiplicamos por el peso corporal y lo dividimos entre 1000. Entonces: (47,46*Peso) / 1000 (47,76*60)/1000 Lobito Inmaculado tiene Vo2max 2847,6 / 1000 = 2,8476 litros / minuto

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