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Relative Velocity. Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero What is Mr. Fox’s velocity relative to Ms. Wood?
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Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
An Introduction to Acceleration: Learning Goal • The student will interpret and solve example questions related to uniformly accelerated motion. (B3.2) Vocabulary: acceleration (B2.1)
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or: v2 = final velocity and v1 = initial velocity
Acceleration Acceleration will have units of m/s/s or m/s2. (Notice also that acceleration is a vector.)
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration? His acceleration is 2.4 m/s2 [E].
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration? His acceleration is 0.75 m/s2 [backward].
Rearranging the Equation The equation that represents the definition of acceleration may be rearranged to solve for any of the other variables, e.g.
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s? Its velocity is 7.6 m/s [down].
More Practice Homework: Acceleration Tomorrow: Acceleration Lab