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Chemical Cells. Chemical Energy Heat Energy. When magnesium powder is added into copper(II) sulphate solution, the temperature of the mixture rises. Displacement reaction occurs. Chemical Energy Heat Energy. Chemical Energy Heat Energy. Overall equation (Redox reaction):
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Chemical Energy Heat Energy • When magnesium powder is added into copper(II) sulphate solution, the temperature of the mixture rises. • Displacement reaction occurs. • Chemical Energy Heat Energy
Chemical Energy Heat Energy • Overall equation (Redox reaction): Mg(s) + CuSO4(aq) MgSO4(aq) + Cu(s) • Ionic equation: Mg(s) + Cu2+(aq) Mg2+(aq) + Cu(s) • Half equations: Mg(s) Mg2+(aq) + 2e- Oxidation Cu2+(aq) + 2e- Cu(s) Reduction
Chemical Energy Heat Energy • Observable changes: • mass of the magnesium strip decreases • copper deposits on the copper strip • blue colour of solution fades out.
Chemical Energy Electrical Energy • When electrons flow through an external circuit, a simple chemical cell is formed. • Chemical Energy Electrical Energy
Chemical Cellof Mg/Cu couple • Magnesium is more reactive than copper, it oxidizes and loses electrons to form positive ions more readily. Mg(s) Mg2+(aq) + 2e- • Magnesium ions dissolve into the solution. • Thus the mass of magnesium strip decreases.
Chemical Cellof Mg/Cu couple • Electrons flow through the external circuit to the copper strip. • Voltmeter shows positive deflection.
Chemical Cellof Mg/Cu couple • Copper(II) ions in electrolyte move to the copper strip. They reduce and gain electrons to form copper atoms. Cu2+(aq) + 2e- Cu(s) • Thus copper deposits on the copper strip.
Simple chemical cell • Basic requirements: Two different metals dipped in a solution of electrolyte
Simple chemical cell • The more reactive metal forms ions more readily. It oxidizes and loses electrons. It becomes the negative electrode. • The less reactive metal becomes the positive electrode. • Positive metal ions dissolves into the electrolyte and electrons flow from the more reactive metal through the external circuit to the less reactive metal.
Simple chemical cell • The voltage of the cell gives a measure of how strongly the electrons are ‘pushed’ through the circuit, and is measured by a voltmeter. • The voltmeter should be correctly connected. • The negative terminal should be connected to the more reactive metal while the positive terminal to the less reactive metal. • Positive ions in electrolyte move to the less reactive metal. They reduce and gain electrons to form metal.
Comparing the tendency to form ions of different metals • The more reactive metal should be connected to the negative terminal of voltmeter.
Comparing the tendency to form ions of different metals • The greater the difference in their tendencies to form ions, the higher is the voltage of the cell.
Chemical cell of Cu/Ag couple • Electrolyte is in the form of filter paper soaked with sodium chloride solution.
Chemical cell of Cu/Ag couple • Copper is more reactive than silver, it oxidizes and loses electrons to form positive ions more readily. Cu(s) Cu2+(aq) + 2e- • Copper(II) ions dissolve into the electrolyte . • Thus the mass of copper strip decreases. • Copper is the negative electrode.
Chemical cell of Cu/Ag couple • Electrons flow from copper through the external circuit to silver. Silver is the positive electrode. • Hydrogen ions in electrolyte move to the silver electrode. They reduce and gain electrons to form hydrogen gas. 2H+(aq) + 2e- H2(g) • Thus effervescence occurs at silver strip. • Overall reaction: Cu(s) + 2H+(aq) Cu2+(aq) + H2(g)
The electrochemical series of metals • Metals arranged in order of their tendencies to form ions. • The order of metals in the electrochemical series is the same as that in their reactivity series (except for the position of calcium).
Modification of simple chemical cell • Two different metals dipped in two separate electrolytes. • The two electrolytes are connected by a salt bridge which can be made by soaking a piece of filter paper in saturated potassium nitrate solution.
Modification of simple chemical cell • Anode (oxidation): Mg(s) Mg2+(aq) + 2e- • Cathode (reduction): Cu2+(aq) + 2e- Cu(s) • Overall equation: Mg(s) + Cu2+(aq) Mg2+(aq) + Cu(s)
Salt bridge • Two main functions: • It completes the circuitby allowing ions to move towards one half cell from the other. • It provides ions to balance the charges in the solutions of the two half cells. • Salt bridge must not be dried. • .
iron(II) sulphate solution acidified potassium permanganate solution Chemical Energy Heat Energy • When excess FeSO4(aq) is added into a purple solution of acidified KMnO4(aq), the colour changes to yellow.
Chemical Energy Heat Energy • Oxidation half equation: • Fe2+(aq) Fe3+(aq) + e • Green yellow • Reduction half equation: • MnO4–(aq) + 8H+(aq) + 5e–Mn2+(aq) + 4H2O() • Purple colourless • Overall equation: 5Fe2+(aq) + MnO4–(aq) + 8H+(aq) 5Fe3+(aq) + Mn2+(aq) + 4H2O()
Other forms of chemical cells: inert electrodes • Anode (oxidation): • Fe2+(aq) Fe3+(aq) + e • Cathode (reduction): • MnO4–(aq) + 8H+(aq) + 5e–Mn2+(aq) + 4H2O() • Overall equation: 5Fe2+(aq) + MnO4–(aq) + 8H+(aq) 5Fe3+(aq) + Mn2+(aq) + 4H2O()
Other forms of chemical cells: inert electrodes • Observable changes: • Green iron(II) sulphate solution changes to yellow • Purple potassium permanganate solution changes to colourless (purple colour fades.)
potassium iodide solution iron(III) sulphate solution Chemical Energy Heat Energy • When excess colourless KI(aq) is added into a yellow solution of Fe2(SO4)3(aq), the colour changes to brown.
Chemical Energy Heat Energy • Anode (oxidation): • 2I-(aq) I2(aq) + 2e • Colourless brown in KI • Cathode (reduction): Fe3+(aq) + e Fe2+(aq) yellow green • Overall equation: 2Fe3+(aq) + 2I–(aq) 2Fe2+(aq) + I2(aq)
Other forms of chemical cells: inert electrodes • Anode (oxidation): • 2I-(aq) I2(aq) + 2e • Cathode (reduction): Fe3+(aq) + e Fe2+(aq) • Overall equation: 2Fe3+(aq) + 2I–(aq) 2Fe2+(aq) + I2(aq)
Other forms of chemical cells: inert electrodes • Observable changes: • Yellow iron(III) sulphate solution changes to green • Colourless potassium iodide solution changes to brown because iodine formed will combine with potassium iodide to form a brown compound. I2(aq) + KI(aq) KI3(aq)