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Instructions and Addressing (cont’d.). Index addressing (1). +. instruction. opcode Reg index. operand. operand. registers. memory or registers. Index addressing (2). Advantages: Allows specification of fixed offset to operand address Disadvantages:
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Index addressing (1) + instruction opcode Reg index operand operand registers memory or registers
Index addressing (2) Advantages: Allows specification of fixed offset to operand address Disadvantages: Extra addition to operand address Notation:ADD X(R1),R3 (X=number) Meaning:[R3] [R3] + M([R1] + X)
Example index addressing Move #E,R0 n Empoyee ID sex age salary Empoyee ID N E Move N,R1 0(R0) 4(R0) Clear R2 program loop 8(R0) Add 8(R0),R2 L 12(R0) 16(R0) Add #16,R0 20(R0) sex age salary Decrement R1 Branch>0 L Move N,R1 Program with index addressing Div R1,R2 Move R2,Sum Q1: What does this program do?
Additional modes Some computers have auto-increment (decrement instructions) Example: (R0)+ Meaning .. M(R0)..; [R0] [R0]+1 Example: -(R0) Meaning [R0] [R0]-1; .. M(R0)..
Additional Instructions Logic instructions Not R0; invert all bits in R0 And #$FF000000,R0; AND with bit string Shift and rotate instructions Many variants for different purposes 6
Logical shifts used in bit Packing Logical shift left 0 C R0 LShiftL #2,R0 . . . before: 0 0 1 1 1 0 0 1 1 . . . virtual: LShiftL #1,R0 0 1 1 1 0 0 1 1 0 . . . after: LShiftL #2,R0 1 1 0 0 1 1 0 0 1 Logical shift right 0 R0 C LShiftR #2,R0 . . . 0 1 1 1 0 0 1 1 before: 0 . . . virtual: 0 LShiftR #1,R0 0 0 1 1 1 0 0 1 . . . after: 0 0 0 1 1 1 0 0 1 LShiftR #2,R0 7
Arithmetic shifts Arithmetic shift right (signed shift) AShiftR #2,R0 R0 C . . . before: 0 1 0 0 1 1 0 1 0 . . . virtual: 0 AShiftR #1,R0 1 1 0 0 1 1 0 1 . . . after: 1 1 1 0 0 1 1 0 1 AShiftR #2,R0 Q1: AShiftR by n bits is equivalent to division by 2n for numbers in 2C or 1C? Tough questions Q2: Rounding negative number shifts towards 0 or -infinity? 8
Rotate Rotate left w/o Carry C R0 RotateL #2,R0 . . . before: 0 0 1 1 1 0 0 1 1 . . . virtual: RotateL #1,R0 0 1 1 1 0 0 1 1 0 . . . after: RotateL #2,R0 1 1 0 0 1 1 0 1 1 Rotate left w/ Carry C R0 RotateLC #2,R0 . . . before: 0 0 1 1 1 0 0 1 1 . . . virtual: RotateLC #1,R0 0 1 1 1 0 0 1 1 0 . . . after: RotateLC #2,R0 1 1 0 0 1 1 0 0 1 9
Assemblers http://www.pds.ewi.tudelft.nl/~iosup/Courses/2011_ti1400_5.ppt
Done so far… History of Computing(1642-2011) Computers Data representation, conversion, and op.Instruction representation and use Lectures 3,4 Programmable Devices Memory organizationProgram sequencingvon Neumann archi.Instruction levels Lecture 2 Digital logicMemory elementsOther building blocks (Multiplexer,Decoder)Finite State Machines Circuit Design Lecture 1 Why Computer Organization Matters? Lecture 0
Problem: How to Program Computers? Computers Data representation, conversion, and op.Instruction representation and use Lectures 3,4 Programmable Devices Memory organizationProgram sequencingvon Neumann archi.Instruction levels Lecture 2 Digital logicMemory elementsOther building blocks (Multiplexer,Decoder)Finite State Machines Circuit Design Lecture 1 Why Computer Organization Matters? Lecture 0
Program Creation and Execution Flow type source program Source in ASCII editor translate assembler listing Source and Object code +error messages object code machine 1 machine 2 link/load linker/loader run input/ output memory image
Three levels of instructions C/C++, Java, … high level programming language program expressed in a high-level language translation instruction set program expressed as a series of instructions Assembler direct implementation fetch/execute implementation program execution in hardware
Instructions and Addressing Introduction Assembler: What and Why? Assembler Statements and Structure The Stack Subroutines Architectures: CISC and RISC 15
Why assembler? [1/2] • Assembler is a symbolic notationfor machine language • It improves readability (vs machine code): • Assembler: Move R0,SUM • Machine code: 0010 1101 1001 0001(16 bits)
Why assembler ? [2/2] Lecture 0 • Speed of programs in critical applications • Access to all hardware resources of the machine • Target for compilers Source: http://www.cs.berkeley.edu/~volkov/cs267.sp09/hw1/results/
Q: Where to get ISA references? Manufacturer’s documentation Third-party manuals (ATTN: may be incorrect)
Q: Does each processor have its own machine language (instruction set)? Shared across generations and even competitors developer.download.nvidia.com/compute/cuda/3_1/toolkit/docs/ptx_isa_2.1.pdf NVIDIA www.eng.ucy.ac.cy/theocharides/Courses/ECE656/ia-32.pdf Intel AMD Cyrix … 1982 1985 1989 1993 1995
Q: Are similar instructions identical on different platforms? Often, they are not NVIDIA Intel AMD Cyrix
Machine Language [1/4] • Is Machine language difficult to learn? • That holds for every unknown language. Machine language is more difficult because you have to work with the specifically defined micro instruction set. • Is Machine language difficult to read and to understand? • Of course, if you do not know the language;however, assembler is more difficult to read and understand than a High Level Language (HLL).
Machine Language [2/4] • Is Machine language difficult to write? • Often HLL languages use libraries to make programming simpler. Machine language programmers often start from scratch. However, full performance may require machine language implementation (or a smart/expensive compiler) • Machine languageprogramming is time consuming • One estimates that the time for coding a program is only 30% of the total development time.
Machine Language [3/4] • Compilers makemachine language superfluous • A good machine language program often looks very different from a compiler generated program. Generally,a C program will win over a hand-made assembly program (unless you’re Michael Abrash … or a student at TU Delft) • Assembler still heavily used for hot/optimized functions (esp. scientific codes), real-time platforms, embedded systems, …
Machine Language [4/4] • Is Machine language difficult to maintain? • Maintainable programs are not specifically dependent on the language they are written in, but more on the way they are contructed • Is Machine language difficult to debug? • Often debuggers output both the HLL and the machine language, and the error can only be found in the generated machine language
Case-in-Point • Universele Brander Automaat (UBA)
Case Universele Brander Automaat Klant: Nefit Fasto B.V. Markt: HVAC (AirCo) Ontwikkelen (1990) en produceren (100k/jaar) van de UBA universele brander- automaat voor Nefit Fasto voorzien van een bipolaire Application-Specific Integrated Circuit (ASIC). Eerste product met een universeel karakter, die een fail-safe approval heeft.
Case Universele Brander Automaat Ignition 230V , Pump and Fan 6 schakel ingangen 8 analoge ingangen 3 schakeluitgangen 3 modulerende uitgangen 2 draads communicatie bus Externe KIM module aansluiting met 178 bytes config settings ASIC and micro-Computer
UBA software opbouw HWIO Application C- language 15 Kbyte 1 Kbyte
UBA micro computer HWIO MC68HC05B16 24 I/O bi-directional 8 A/D analogue inputs 2 TCAP input timers 2 TCMP output compare 2 PWM D/A outputs 1 SCI serial output 1 COP watchdog 256 bytes RAM 256 bytes EEPROM 16 Kbytes (EP)ROM 1 Kbytes
UBA PuR After Power up Reset special routine[ see also The Zen of Diagnostics, http://www.ganssle.com/articles/adiags1.htm ] - all instruction set in test routine - 16-bit CRC (99,98% data integrity) - Walking A0 and 05 RAM test (pattern sensitivity) - Check on A/D (converter linearity) - Main loop partitioned in modules - Module check in each phase - Acknowledge module check by pulse to ASIC (350ms) - Interrupt program termination check by pulse to ASIC (20ms)
UBA Assembly • Check instruction set • Test of each opcode over and over again • Emergency stop at fault detection • Not possible in “C” • Check memory • As part of the program • Emergency stop at fault detection • Difficult in “C” • Better control on application • Compiler generated code must be checked for correctness.
Instructions and Addressing Introduction Assembler: What and Why? Assembler Statements and Structure The Stack Subroutines Architectures: CISC and RISC 32
Assembler Statements • Declarations • no code generation • memory reservation • symbolic data declarations • where to start the code execution • Executable statements • are translated to real machine instructions (often, one-to-one)
Data declarations Label operation operand S EQU 200 ORIGIN 201 N DATA 300 N1 RESERVE 300 ORIGIN 100
Program Addr operation operand START Move N,R1 Move #N1,R2 Clear R0 LOOP Add (R2),R0 Incr R2 Decr R1 Branch>0 LOOP Move R0,S Return End START
Memory lay-out S Move N,R1 100 200 N ..... 300 101 201 ..... ..... 102 202 N1 ..... ..... 103 203 ..... ..... 104 ..... ..... 105 Branch >0 106 107 501 Nn
Structure assembler [1/3] • Assembler is hardly more than substitution • substitute 0001 for Move • substitute 0000 0000 0000 0101for#5 • Assembler is level above machine language • Assembler languages for different architectures are alike, but not identical
Structure assembler [2/3] Assembler programs contain three kind of quantities: • Absolute: • opcodes, contants:can be directly translated • Relative: • addresses of instructionswhich are dependent of final memory location • Extern: • call to subroutines
Structure assembler [3/3] • Literals:constants in programs • Some assemblers act as if literals are immediate operands • Example: Load #1 is equivalent to: Load One ... One: 1
Number notation • Numbers can be represented using various formats: ADD #93,R1 or ADD #%01011101,R1 or ADD #$5D,R1
Instructions and Addressing Introduction Assembler: What and Why? Assembler Statements and Structure The Stack Subroutines Architectures: CISC and RISC 41
The Stack Main idea • (Large?) Memory space used to store program data • Items are added to the stack through a PUSH operation • Items are removed from the stack through a POP operation Details • Often, a stack is a contiguous array of memory locations • Often, any number of stacks can be set up by a program • Often, only one stack can be used at a time (changing the active stack possible at any time) Q1: Why use stacks? Q2: Implications?
Stack registers CPU SP PC Stack Pointer Main Memory
70 300 20 10 60 Stack operations 0 1 SP
Push Subtract #4,SP Move R0,(SP) 0 SP 1 80 70 300 or: Move R0,-(SP) 20 10 60 80 R0
Pop 0 Move (SP),R0 Add #4,SP 1 80 70 SP 300 or: Move (SP)+,R0 20 10 60 70 R0
Instructions and Addressing Introduction Assembler: What and Why? Assembler Statements and Structure The Stack Subroutines Architectures: CISC and RISC 47
Subroutines • More structure in programs • Mimics procedure and function callsin High Level programming Languages (HLL)
Calling mechanism Call SUB 200 next instr. 204 PC Link ................ 204 1000 ................ PC Link RTS 204
Question Is a Link register sufficient ?