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P.1. AL E-field Solution. P.4. Total charges = (+4 x 10 -6 ) + (-1 x 10 -6 ) = (+3 x 10 -6 ) C. Charges in each sphere = +1.5 x 10 -6 C. F E. W=10 -3 N. P.5. 10 o. 0.05m. d. P.5. 2 out of 4 possible cases. F 1 : F 2 = 5 : 9. F 1 : F 2 = 5 : 4. P.8. Neutral point. P.8.
E N D
P.1 AL E-field Solution
P.4 Total charges = (+4 x 10-6) + (-1 x 10-6) = (+3 x 10-6) C Charges in each sphere = +1.5 x 10-6 C
FE W=10-3 N P.5 10o 0.05m d
P.5 2 out of 4 possible cases F1 : F2 = 5 : 9 F1 : F2 = 5 : 4
P.8 Neutral point
P.8 Neutral point + + + + + + + + + + - - - - - - - - - - - - - What will happen ?
P.8 Neutral point + + + + + + + + + + - - - - - - - - - - - - -
P.8 Neutral point ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- - - - What will happen ?
P.8 Neutral point ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- - - - E
P.8 Neutral point ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- - - - Same effect
P.8 Neutral point - - - ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- Due to edge effect, E
P.8 Neutral point ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- - - - What will happen?
P.8 Neutral point ++ ++ ++ ++ ++ ++ ++ ++ ++ ++ -- -- -- -- -- -- -- -- -- -- - - - E
+ + + + + + + + E E P.8
+ + + + + + + + E=0 P.8 No electric force inside the shell
P.9 Φ Φ Φ A Less effective area Effective area=0 Effective area = A
E P.10 R r
+ + + + + + + + P.10 Uniformly charged sphere E r R
+ + + + + + + + P.11 Hollow sphere E r R
P.8 Parallel Plane a + + + + + + + + + + - - - - - - - - - - A
W=mg W FE P.13 No
P.13 E Horizontal component, Vertical component, θ g
T T FE P.13 T = k x = (10)(0.55-0.5) = 0.5
P.14 a) A(-ve) and B(-ve) b) A(+ve) and B(+ve)
d F1 P.14 F2 F3 Vertical component,
F3 F1 P.14 d F4 F2 In diagonal direction
15o TB TA 15o FE WA=mAg WB=mBg P.5 30o WA=mAg TA 105o FE 45o
15o TB TA 15o FE WA=mAg WB=mBg P.5 60o TB 45o WB=mBg FE 75o
+Q0 E F P.16 A B C +Q r Δx x
P.17 V +ve charge r -ve charge
+ + + + + + + + P.18 Uniformly charged sphere V r R
+ + + + + + + + P.18 Solid / hollow conducting sphere V r R
P.18 Parallel Plane A B + + + + + + + + + + - - - - - - - - - - P r d
B A P S L C P.19 ++++++++++++++++ What will happen ?
B A P S L C P.19 ++++++++++++++++ ++++++++++++++++ Increase in divergence +++++++++ ++++++
B A P S L C P.19 ???????????????????? ++++++++++++ What is it ? +++++++++++ ++++++++
B A P S L C P.19 +++++++++++++++++ ++++++++++++ Positively charged rod +++++++++++ ++++++++
B A P S L C P.19 ---------------------- ++++++++++++++++ What will happen ? +++++++++ ++++++
B A P S L C P.19 ---------------------- ++++++++++++++++++ Decrease in divergence ++++++++ +++++
- + + - - - + + + - P.19 - Ions will be produced Ions will be attracted by the other charged objects +
- + + - - - + + + - P.20 Increase in divergence +++ ++
- + + - - - + + + - P.20 Increase in divergence +++ ++
P.20 No reading No potential difference Same potential Equipotential line
P.20 With reading Have potential difference Different potential Equipotential line
+Q E P.21 A B +Q0 x Δx -ve +ve +ve
P.24 A B d - - - - - - - - - - + + + + + + + + + + P r Q l 800 400 600 200