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Perception and Decision-making: Going Beyond Surface Information

"Norma Cenva's unpublished laboratory notes highlight the limitations of relying on superficial information for important decisions. This article explores the phases present in steels, their formation, and the significance of understanding microstructures in steel alloys."

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Perception and Decision-making: Going Beyond Surface Information

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  1. The eyes of common perception do not see far. Too often we make the most important decisions based only on superficial information –Norma Cenva (unpublished laboratory notes)

  2. Problem 10.14 List all phases that can be present in steels (do not include the alloy carbide phases or consider stainless steels); describe how each can be formed. AUS - heat above A1 FE - cool AUS slowly to below A1 CM - cool AUS slowly to below A1 MAR - quench to below ms (also - liquid & -ferrite)

  3. Problem 10.14 AUS, FE, CM, MAR For these phases, which can occur in: hypoeutectoid steels hypereutectoid steels a eutectoid steel

  4. Problem 9.55 Compute fractions of proeutectoid ferrite and pearlite for Fe-0.25C alloy. Why was this problem assigned? Understand the terms proeutectoid ferrite and pearlite Learn to use the equilibrium Fe-C diagram See that diagram tells amounts of microconstituents The concept is important; resulting nos. are not (as far as course is concerned)

  5. Problem 9.55 Gives proeut. FE fraction: (0.77-0.25)/0.75 = 0.69 Compute fractions of proeutectoid ferrite and pearlite for Fe-0.25C alloy.

  6. Problem 9.55 proeut. FE fraction = 1 Compute fractions of proeutectoid ferrite and pearlite

  7. Problem 9.55 proeut. FE fraction = 0.25 proeut. FE fraction = 0 Compute fractions of proeutectoid ferrite and pearlite

  8. Problem 9.57 Total FE = 0.9, total CM = 0.1. Hypo or hyper? Why was this problem assigned? Use the terms hypoeutectoid, hypereutectoid Total FE, total CM? (where's the beef?) More contact with Fe-C diagram

  9. Problem 9.57 Total FE = 0.9, total CM = 0.1. Hypo or hyper? Total FE = 0.9 = (6.67-x)/6.65 x = 0.68

  10. Problem 10.14 Use TTT curves predict microstructures when steel is cooled as specified Why was this problem assigned? Understand TTT curves Connect cooling process with microstructure Recognize variety of microstructures possible

  11. Problem 10.14 Use TTT curves predict microstructures when steel is cooled as specified ~ 2/3 P, 1/3 MAR Transformation of AUS not complete till almost 105 s

  12. Problem 10.14 Use TTT curves predict microstructures when steel is cooled as specified Roughly 2/3 bainite + 1/3 MAR

  13. Problem 10.14 Use TTT curves predict microstructures when steel is cooled as specified Tempered MAR

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