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Thursday, May 15 th : “A” Day Friday, May 16 th : “B” Day Agenda

Thursday, May 15 th : “A” Day Friday, May 16 th : “B” Day Agenda. Collect Crossword Puzzle Collect Concept Review Ch. 15 Review – pass back/warm-up Ch. 15 Test Looking Ahead Mon/Tues: Finals Review Wed/Thurs: Fun Lab/Sr. Finals (Thurs)

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Thursday, May 15 th : “A” Day Friday, May 16 th : “B” Day Agenda

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  1. Thursday, May 15th: “A” DayFriday, May 16th: “B” DayAgenda • Collect Crossword Puzzle • Collect Concept Review • Ch. 15 Review – pass back/warm-up • Ch. 15 Test Looking Ahead • Mon/Tues: Finals Review • Wed/Thurs: Fun Lab/Sr. Finals (Thurs) • Fri/Tues: Sr. Finals (Fri)/2nd Semester Final Jeopardy

  2. Ch. 15 Review/Warm-up #21 Write an equation for the reaction between hydrocyanic acid, HCN, and water. Label the acid, base, conjugate acid and conjugate base. HCN + H2O ? HCN + H2O CN- + H3O+ Acid Base Conjugate Base Conjugate Acid

  3. Ch. 15 Review/Warm-up #40 If the hydronium ion concentration of a solution is 1.63 X 10-8 M, what is the hydroxide ion concentration? [H3O+] [OH-] = 1.00 X 10-14 M (1.63 X 10-8 M) [OH-] = 1.00 X 10-14 M [OH-] = 6.13 X 10-7 M

  4. Ch. 15 Review/Warm-up # 47 If [OH-] of an aqueous solution is 0.0134 mol/L, what is the pH? pH = -log [H3O+] [H3O+] [OH-] = 1.00 X 10-14 M [H3O+] (0.0134 M) = 1.00 X 10-14 M [H3O+] = 7.46 X 10-13 M pH = -log (7.46 X 10-13 M) pH = 12.1

  5. Ch. 15 Review/Warm-up #49 LiOH is a strong base. What is the pH of a 0.082 M LiOH solution? pH = -log [H3O+] LiOH Li+ + OH- 0.082 M 0.082 M [H3O+] [OH-] = 1.00 X 10-14 M [H3O+] (0.082 M) = 1.00 X 10-14 M [H3O+] = 1.2 X 10-13 M pH = -log (1.2 X 10-13 ) pH = 13 (2 sig figs)

  6. Ch. 15 Review/Warm-up # 63 What is the hydroxide ion concentration in a solution of pH 8.72? [H3O+] = 10-pH [H3O+] = 10-8.72 [H3O+] = 1.91 X 10-9 M [H3O+] [OH-] = 1.00 X 10-14 M 1.91 X 10-9 M [OH-] = 1.00 X 10-14 M [OH-] = 5.24 X 10-6 M

  7. Ch. 15 Review/Warm-up #78 If 50.00 mL of 1.000 M HI is neutralized by 35.41 mL of KOH, what is the molarity of the KOH? HI + H2O I- + H3O+ 1.000 M 1.000 M (C OH-) (V OH-) = (C H3O+) (V OH-) (C OH-) (0.03541 L) = (1.000 M) (0.05000 L) (C OH-) = 1.412 M KOH K+ + OH- 1.412 M 1.412 M

  8. Ch. 15 Test“Acids and Bases” • You may use your notes, a periodic table, ion charts, and a calculator.

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