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Balancing Chemical Reactions

Balancing Chemical Reactions. Why?. There are laws!!!!. Matter cannot be created or destroyed only changed. So if you start with 20 hydrogen, you end up with 20 hydrogen. HC 2 H 3 O 2 + NaHCO 3. NaC 2 H 3 O 2 + H 2 O + CO 2. Equations. Vinegar + Baking Soda. Products. Word Equation.

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Balancing Chemical Reactions

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  1. BalancingChemical Reactions Why?

  2. There are laws!!!! • Matter cannot be created or destroyed only changed. So if you start with 20 hydrogen, you end up with 20 hydrogen

  3. HC2H3O2 + NaHCO3 NaC2H3O2 + H2O + CO2 Equations Vinegar + Baking Soda Products Word Equation Reactants White Powder + Clear Liquid + Bubbles Formula Equation

  4. HC2H3O2 + NaHCO3 NaC2H3O2 + H2O + CO2 HCCHHHOO + NaHCOOO NaCCHHHOO + HHO + COO (5H, 3C, 5O, Na) (5H, 3C, 5O, Na) 14 atoms 14 atoms Balancing a Formula

  5. Ag + H2S Ag2S + H2 2Ag, 2H, S 2Ag, 2H, S Balanced? Ag2S + H2 Ag + H2S Ag, 2H, S 2Ag, 2H, S If not….The ONLY thing you can do is multiply the number of MOLECULES you have. You do this by putting a coefficient in front of the MOLECULE. The 2 multiplies everything after it until you have a different molecule. 2

  6. Step 1: list all the elements underneath the reactants and products Step 2: Count how many atoms of each element are on the reactant side and the product side Balance the following 3rd Step: Put numbers (coefficients like 1, 2, 3, 4, 5 etc..) in front of the compounds that you are short on. This multiplies all of the atoms in the compound. When you do that, you may have to change the other side as well. 2 2 2 Why is it 4? Because 2 H from NaOH and 2 H from H2 are added 1 2 1 2 Na + H2O NaOH + H2 Na= Na= H = H = O = O = 2 4 3 4 1 2 1 2 BALANCED So what do we need to do?

  7. 3rd Step: Put numbers (coefficients like 1, 2, 3, 4, 5 etc..) in front of the compounds that you are short on. This multiplies all of the atoms in the compound. When you do that, you may have to change the other side as well. Step 2: Count how many atoms of each element are on the reactant side and the product side Step 1: list all the elements underneath the reactants and products Balance the following Why did I put the 2 in front of H2O instead of O2? 2 2 H2O + O2 H2O2 H = H = O = O = 2 4 2 4 Because only changing O2 would not help me with the H. 3 4 2 4 So what do we need to do? BALANCED

  8. 2 2 2 1 2 2 4 2 4 CaCl2 Ca2 + Cl2 Ca= Ca= Cl = Cl = BALANCED

  9. 6 4 3 2 3 2 2 2 1 1 2 Al + NaOH Na3AlO3 + H2 Al= Al= Na= Na =O = O = H = H = 1 3 4 6 6 3 1 3 4 6 3 6 2 4 6 1 3 4 6 BALANCED

  10. Now you do some at your desk Zn + HCl ZnCl2 + H2 Al + O2 Al2O

  11. 2 1 1 Zn + HCl ZnCl2 + H2 Zn= Zn= H= H = Cl = Cl = 2 1 2 2 1 2 BALANCED

  12. 4 2 1 4 2 4 Al + O2 Al2O Al= Al= O = O = 2 1 2 BALANCED

  13. Zn + 2HCl  ZnCl2 + H2 • 12Al + 3O26Al2O

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