1 / 10

MEKANIKA REK A YASA 1

MEKANIKA REK A YASA 1. Pengertian Gaya Momen dan Pengertian statis tertentu Perletakan dan macam konstruksi Gaya = Normal, Lintang, Momen Bidang = Normal, Lintang Momen Konstruksi 3 sendi = Portal dan Pelengkung 3 sendi Balok Gerber Garis Pengaruh pada balok dan portal 3 sendi.

yamin
Download Presentation

MEKANIKA REK A YASA 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. MEKANIKA REKAYASA 1 • Pengertian Gaya • Momen dan Pengertian statis tertentu • Perletakan dan macam konstruksi • Gaya = Normal, Lintang, Momen • Bidang = Normal, Lintang Momen • Konstruksi 3 sendi = Portal dan Pelengkung 3 sendi • Balok Gerber • Garis Pengaruh pada balok dan portal 3 sendi

  2. Gaya,Beban, dan Perletakan • Gaya Vektor= Besaran yang mempunyai harga,arah dan titik awal • Vektor Bidang Ruang Beban Terpusat/Garis (ton,kg) Terbagi Rata/Merata(ton/m , kg/m)

  3. Perletakan • Roll • Sendi V H • V • Jepit H M V • Pendel A B

  4. Perjanjian Tanda Arah • V H P • A B • ½ L ½ L + - - +

  5. Contoh soal • P=3V2 • A C B • Sin 45=Pv/p MB=0 MA=0 • =Pv/3v2 VA.10-Pv.6 =0 VB.10-3.4=0 • Pv = sin 45.3v2 VA.10-3.6 =0 VB=12/10 Pv = 1,5.2 VA.10 =18 VB=1,2 T Pv = 3 VA =1,8 T 4m 6m

  6. Gaya Normal • Gaya yang arahnya tegak lurus bidang penampang • Dapat berupa : • Gaya Tarik (+)meninggalkan titik simpul • Gaya Tekan (-)menuju titik simpul

  7. Gaya Lintang • Gaya yang Arahnya sejajar dengan bidang penampang - +

  8. Gaya Momen • Gaya akibat beban Lendutan + - -

  9. Bidang D • X Q • A C B • ½ L ½ L • MB=0 MA=0 • VaxL-qL.L/2=0 VB.L-QX.1/2L=0 • Va=1/2 qL2=1/2qL VB=1/2QL • L • =1/2 QL

  10. Gaya Lintang • Di A x=o DA = ½ q.l – q.o=1/2ql • Di C x=1/2l DC=1/2ql-qx1/2l=o • Di B x=l DB= ½ ql=-1/2ql • + • A C - B

More Related