Activity Series

1. Activity Series

3. We are going to ignore the second half for today • And we will ignore the halogens for now • Leaving a list of metals

4. This list has the most reactive metals on the top and the least reactive metals on the bottom. • Meaning the elements in the top would rather be in a compound more then the elements on the bottom.

5. A single replacement reaction will only happen if the element by itself is higher on the list then the element in the compound. • For example: • Ni + KOH  • Find Ni • Find K • Ni is lower then K so this will not react. We would write “No rxn” No rxn

6. Cu + AlCl3 • Here is another example: • Al + CuCl2 • Find Al • Find Cu • Al is higher then Cu so this can react. • We can then write the products. • What element will be by itself now? • What will the compound look like? • Balance

7. Ag + Mn(NO3)2 • Here is another example: • Mn + AgNO3 • Find Mn • Find Ag • Mn is higher then Ag so this can react. • We can then write the products. • What element will be by itself now? • What will the compound look like? • Mn will have a +2 charge • In other problems it will be Mn(II) • Balance

8. No rxn • Here is another example: • Sn(IV) + NaCN • Find Sn • Find Na • Sn is lower then Na so this is no reaction

9. Practice • Na + ZnSO4 • Cr(II) + Fe2O3  • Pb(II) + CaCO3  • Fe(III) + PbI2  • K + LiOH 

10. The halogen • This works the same way with the halogens • Example: • Br2 + NaCl • Bromine is below chlorine so its no reaction.

11. The halogen • Example: • F2 + KI  • Fluorine is above Iodine so this will react. • What element will be by itself now? • What will the compound look like? • Balance

12. Practice • F2 + AlCl3 • I2 + ZnCl2  • Cl2 + FeBr2 