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Solving A System of Equations

Solving A System of Equations. Milagros Duran & Keslie Chapa December 18, 2013 7+8A. Problem Situation. A pair of boots and a pair of tennis shoes cost $196.12. The difference in their cost is $44.38. Determine the cost of each . Define Variables. X = cost of a pair of boots

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Solving A System of Equations

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  1. Solving A System of Equations Milagros Duran & Keslie Chapa December 18, 2013 7+8A

  2. Problem Situation • A pair of boots and a pair of tennis shoes cost $196.12. The difference in their cost is $44.38. Determine the cost of each.

  3. Define Variables X= cost of a pair of boots Y= cost of a pair of tennis shoes

  4. System of Equations X –Y = 44.38 X + Y = 196.12

  5. Solution Method • Elimination • Add the equations to eliminate the variable Y.

  6. Step 1 of Solution • X + Y = 196.12 Add the equations • X –Y = 44.38 • 2X = 240.50 • X = 120.25

  7. Step 2 of Solution • X + Y = 196.12 Rewrite knowing that X equals 120.25 • 120.25 + Y = 196.12 Subtract 120.25 from both sides. • Y = 75.87

  8. Solution to the System of Equations • (X, Y) • (120.25, 75.87)

  9. Check of Solution • 151.74+44.38=196.12

  10. Solution in the Problem Situation The cost of a pair of boots is $120.25. The cost of a pair of tennis shoes is $75.87.

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