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   RS = PQ = SQ =    SR = QP = QS =  RP =

Solution. Write the following vectors in terms of a and b. 2 a. Q. P. b. R. S. a.    RS = PQ = SQ =    SR = QP = QS =  RP =. a. 2 a. b. - a. -2 a. - b. b - a. Write the following vectors in terms of p and q (ABCD is a parallelogram).

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   RS = PQ = SQ =    SR = QP = QS =  RP =

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  1. Solution Write the following vectors in terms of a and b 2a Q P b R S a  RS = PQ = SQ =  SR = QP = QS =  RP = a 2a b -a -2a -b b - a

  2. Write the following vectors in terms of p and q (ABCD is a parallelogram) Solution p A B q D C      (i) DA (ii) CD (iii) DB (iv) AC (v) CA q q + p p - q q - p -p

  3. Write the following vectors in terms of a and b a B A b a B A 4a C F b O F C b D E 3a E D       1) 2) i) FC ii) DA iii) EB iv) EA v) FD i) AC ii) FA iii) FD iv) DC v) AE    

  4. Solution a  (i) AC = a + b B A  b (ii) FA =3a - b 4a  (iii) FD = b + 3a C F  (iv) DC = a - b  b (v) AE = D E 3a (1) 2b - 3a

  5. Solution   (i) FC = 2a (ii) DA = - 2b a B A  (iii) EB = 2(a - b) b O F  C (iv) EA =  (v) FD = b + a E D (2) a - 2b

  6. Rewrite the following vectors in terms of a and b Solutions • OB • ii) CA a C B c c D a A OB = OC + CB OB = c + a

  7. Solutions • OB • ii) CA a C B c c O a A OB = OC + CB CA = CB + BA OB = c + a CA = - c + a

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