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Kontinuitas aliran

Kontinuitas aliran. ARWI IMAM PRATAMA 20110110112 TEKNIK SIPIL C. 1. Diketahui : D1= 300 mm D2= 100 mm D3= 200mm Debit Q1= 50 lt / dt Kecepatan V2= 1 m/ dt Di tanya : Debit Q2, Q3 dan V3?. Jawab : Luas penampang : A1 = 1/4.

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Kontinuitas aliran

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  1. Kontinuitasaliran ARWI IMAM PRATAMA 20110110112 TEKNIK SIPIL C

  2. 1. Diketahui : D1= 300 mm D2= 100 mm D3= 200mm Debit Q1= 50 lt/dt Kecepatan V2= 1 m/dt Di tanya : Debit Q2, Q3 dan V3?

  3. Jawab : Luaspenampang : A1 = 1/4. =1/4..(0.3)= 0,07065 m² A2= 1/4. =1/4..(0.1)=0,00785 m² A3 = 1/4. =1/4..(0.2)=0,0314 m² Debit : Q 2 =A2 x V2 = 0,00785 x 1=0,00785 m³/dt=7,85 lt/dt

  4. HukumKontinuitas : Q1=Q2 X Q3 Q3=Q1- Q2 =0,05 - 0,00785 =0,04215 m3/dt =4215 lt/dt V3= = =1,34 m/dt

  5. 2. Diketahui: Diameter: D1=300 mm D2=150 mm Kecepatan:V1=1 m/dt Ditanya: Q1, Q2, danV2?

  6. Jawab: Luaspenampang A1= ¼.π. D1² = ¼π. ( 0,3 )²= 0,07065 m² Debit Q1=A1 . V1 =0,07065 x 1 =0,07065 m³/dt =70,65 lt/dt

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