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Unit 1 Book Problems p. 164

Unit 1 Book Problems p. 164. 1) 4 2) 4,512 3) a. 0.06235 b. 7229 c. 0.000005001 d. 86210 4) a. -5 b. 6 c. -4 d. 4. 5) a. 9.367421 X 10 6 b. 7.241 X 10 3 c. 5.519 X 10 -4 d. 5.408 X 10 0 e. done f. 6.319 X 10 1

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Unit 1 Book Problems p. 164

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  1. Unit 1 Book Problems p. 164 • 1) 4 • 2) 4,512 • 3) a. 0.06235 • b. 7229 • c. 0.000005001 • d. 86210 • 4) a. -5 • b. 6 • c. -4 • d. 4 • 5) a. 9.367421 X 106 • b. 7.241 X 103 • c. 5.519 X 10-4 • d. 5.408 X 100 • e. done • f. 6.319 X 101 • g. 7.215 X 10-9 • h. 7.21 X 10-1

  2. 6) a. 483 • b. 0.0007221 • c. 6.1 • d. 0.0000000911 • e. 4,221,000 • f. 0.00122 • g. 9999 • h. 0.00001016 • i. 101,600 • j. 0.411 • k. 97,100 • l. .000971 • 7) a. 1.423 X 105 • b. 7.741 X 10-13 • c. 2.27 X 104 • d. done • e. 2.51 X 102 • f. 9.7522 X 101 • g.9.7752 (X 100) • h. 4.4252 X 108 • 9) a. 103 • b. 10-2 • c. 10-3 • d. 10-1 • e. 10-9 • f. 10-6

  3. 10) a. mega • b. milli • c. nano • d. mega • e. centi • f. micro • 18) d • 22) estimated – 2.85 appears to between two of the smallest scale marks each of which is .1 • 23) scale is to nearest .1 cm and estimating 2.850 would imply the scale is to .01 cm • 24) a. 4 • b. 5 • c. 4 • d. 1 • e. 3 • f. 3 • g. 6 • h. 5

  4. 25) a. 2 • b. indefinite • c. indefinite • b & c are definitions or conversion factors • d. 1 • e. 1 • 26) a. 1,570,000 • b. 2.77 X 10-3 • c. 84,600 • d. 0.00117 • e. 0.0776 • 27) a. 3.42 X 10-4 • b. 1.034 X 104 • c. 1.7992 X 101 • d. 3.37 X 105 • 28) 2 • 29) 3 • 30) 1 • 31) none • 32) a. 641.0 • b. 1.327 • c. 77.34 • d. 3215

  5. 33) a. 124 • b. 1.995 X 10-23 • c. 0.0114 • or 1.14 X 10-2 • d. 5.3 X 10-4 • 40) a. 254.3 g 1kg 1000g = .2543 kg b. 2.75 kg 1000g = 2750g 1 kg • 44) 212oF or 100oC • 45) 100 degrees • 47) a. 118 K • b. 473 K • c. 221 K • 48) a. 2oC • b. 172oC • c. -273oC • d. -196oC • e. 9727oC • f. -271oC • 51) volume • 52) lead • 53) low

  6. 54) density is characteristic of pure substances • 55) aluminum • 57) D = 75.2 g 89.2 mL = 0.843 g/mL 58) 1.45 kg 1000g 542 mL 1 kg = 2.68 g/mL • 60) 10.5 g/cm3 = 5.25 g volume volume = 5.25 g 10.5 g/cm3 = .5 mL+ 11.2 mL = 11.7 mL

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