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agust,www,...januar09/Profun-090209ak.ppt. 4). 2). 3). 1). 1) Ed(0), J´= 0 – EVv´=8,J´= 0 = 45.553 cm-1. 2) EVv´=9, J´= 5 – EDv´=0,J´= 5 = 164.24 cm-1. 3) Ef(2), J´= 5 – EVv´=8,J´= 5 = 17.14 cm-1. 4) EVv=10, J´= 3 – Egv=0 J´= 3 = 106.64 cm-1.
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4) 2) 3) 1) 1) Ed(0), J´=0 – EVv´=8,J´=0 = 45.553 cm-1 2) EVv´=9, J´=5 – EDv´=0,J´=5 = 164.24 cm-1 3) Ef(2), J´=5 – EVv´=8,J´=5 = 17.14 cm-1 4) EVv=10, J´=3 – Egv=0 J´=3 = 106.64 cm-1 agust,heima,...january09/Profun-080209ak.pxp <= agust, heima, ...january09Term values for triplet paper-080209kmak.xls
D1P1(v´=0) agust, heima, ...january09/Term values for triplet paper-090209kmak.xls